Answer:
(- 2, 4 )
Step-by-step explanation:
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) , then the midpoint is
( 
, 
)
Here (x₁, y₁ ) = A (4, 6 ) and (x₂, y₂ ) = B (- 8, 2 )
midpoint = ( 
, 
) = ( 
, 
) = (- 2, 4 )
Answer:
a. n x (2n +1) = 10
b. length: 5 width: 2
Step-by-step explanation:
5 is 1 more then 2 times 2
Answer:
The correlation between exam score and amount of time spent on the exam is an example of a <u>negative correlation</u>.
Step-by-step explanation:
Consider the provided statement.
College professor reports that students who finish exams early tend to get better grades than students who hold on to exams until the last possible moment.
That means the student who finish the exam early will get the highest marks. One who finish after the first student will get second highest mark and the one who finish in the end will get the least marks.
Now consider time as first variable and marks as second variable.
That means as the first variable increase the second variable decreases.
According to the definition of Negative correlation: It is a relationship between two variables in which one variable increases as the other decreases, and vice versa.
Hence, the correct answer is negative correlation.
Answer:
a) <u>0.4647</u>
b) <u>24.6 secs</u>
Step-by-step explanation:
Let T be interval between two successive barges
t(t) = λe^λt where t > 0
The mean of the exponential
E(T) = 1/λ
E(T) = 8
1/λ = 8
λ = 1/8
∴ t(t) = 1/8×e^-t/8 [ t > 0]
Now the probability we need
p[T<5] = ₀∫⁵ t(t) dt
=₀∫⁵ 1/8×e^-t/8 dt
= 1/8 ₀∫⁵ e^-t/8 dt
= 1/8 [ (e^-t/8) / -1/8 ]₀⁵
= - [ e^-t/8]₀⁵
= - [ e^-5/8 - 1 ]
= 1 - e^-5/8 = <u>0.4647</u>
Therefore the probability that the time interval between two successive barges is less than 5 minutes is <u>0.4647</u>
<u></u>
b)
Now we find t such that;
p[T>t] = 0.95
so
t_∫¹⁰ t(x) dx = 0.95
t_∫¹⁰ 1/8×e^-x/8 = 0.95
1/8 t_∫¹⁰ e^-x/8 dx = 0.95
1/8 [( e^-x/8 ) / - 1/8 ]¹⁰_t = 0.95
- [ e^-x/8]¹⁰_t = 0.96
- [ 0 - e^-t/8 ] = 0.95
e^-t/8 = 0.95
take log of both sides
log (e^-t/8) = log (0.95)
-t/8 = In(0.95)
-t/8 = -0.0513
t = 8 × 0.0513
t = 0.4104 (min)
so we convert to seconds
t = 0.4104 × 60
t = <u>24.6 secs</u>
Therefore the time interval t such that we can be 95% sure that the time interval between two successive barges will be greater than t is <u>24.6 secs</u>
Answer:
C. 2(k +2)(k +5)(k +1)
Step-by-step explanation:
The LCM will be the product of unique factors.
The unique factors are 2, (k+1), (k+2), (k+5), so the LCM is their product:
2(k+1)(k+2)(k+5) . . . . matches choice C
