Question

NEED ASAP

Answer 1

Answer:

(- 2, 4 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) , then the midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

Here (x₁, y₁ ) = A (4, 6 ) and (x₂, y₂ ) = B (- 8, 2 )

midpoint = ( $\frac{4-8}{2}$ , $\frac{6+2}{2}$ ) = ( $\frac{-4}{2}$ , $\frac{8}{2}$ ) = (- 2, 4 )

Answer 2

Midpoint be p(x,y)

P(x,y)=

$\\ \sf\longmapsto \left(\dfrac{4-8}{2},\dfrac{6+2}{2}\right)$

$\\ \sf\longmapsto \left(\dfrac{-4}{2},\dfrac{8}{2}\right)$

$\\ \sf\longmapsto (-2,4)$