Answer:
C. Removing this step decreases the amount of carbon in the air: This is correct, removing factories would decrease the emission of greenhouse gases, thus decreasing CO2 in the atmosphere.
Explanation:
When we look at the picture we can see that the line that goes from G to C, goes from a factory to the atmosphere. As we know factories release a great number of elements into the atmosphere being one of them, carbon dioxide. Therefore taking into consideration we can proceed to analyze the following statements.
A. Removing this step prevents photosynthesis in the next step: This is not true industry increases carbon dioxide in the atmosphere, even if they don't exist there is enough CO2 for plants to perform photosynthesis.
B.Removing this step increases the amount of carbon in the soil: This is not true as factories release carbon dioxide to the atmosphere, not the soil.
C. Removing this step decreases the amount of carbon in the air: This is correct, removing factories would decrease the emission of greenhouse gases, thus decreasing CO2 in the atmosphere.
D. Removing this step increases carbon storage in plants: This is incorrect the carbon storage in plants is cording to their necessities independently of the abundance in CO2, in the atmosphere.
A example of a nerve cell is a nerve cell
Atomic number shows the number of protons in the nucleus of an atom.
Atomic weight shows the is an another term for atomic mass, which means <span>It is approximately equivalent to the number of protons and neutrons in the atom (the mass number) or to the average number allowing for the relative abundances of different isotopes.</span>
Answer:
Barr bodies are small bodies that are dark staining bodies that show the inactivated X chromosome, these sex chromatin bodies attach to the membrane of the nucleus of interphase cells.
One less of the total number of X-chromosome (n-1) represents the number of Barr bodies.
Then,
The number of Barr bodies with Klinefelter would be:
Klinefelter (47,XXY): (n-1) = (2-1) = 1 Barr body as here two X chromosome present.
Similarly, for
Turner (45,XO): (n-1) = (1-1) = 0 Barr bodies (X chromosome = 1)
Now, as per the question, the bar bodies for karyotypes given
47,XYY: (n-1) = (1-1) = 0 Barr bodies
47,XXX: (n-1) = (3-1) = 2 Barr bodies
48,XXXX: (n-1) = (4-1) = 3 Barr bodies
