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3 years ago

Help me please ASAP, I will give Brainliest!!

Mathematics

2 answers:

Flura [38]3 years ago

4 0

Equation: 18(20) * 7 or 18(20) x 7

Snowcat [4.5K]3 years ago

3 0

The expression needed to solve would be 7(18(20))
-
to solve, you can use PEMDAS.

you start to evaluate in the parentheses. in this case that would mean 18*20 and that is 360.

then you multiply 360 by 7 to get 2520.

so your answer is 2,520 and your expression is 7(18(20)) or (18*20)*7. Hope that helps :)

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Please help asap I'm not sure how much time I have

BlackZzzverrR [31]

Tan 37,4 = opposite/adjacent

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• then multiply both sides by 12,8

12,8tan 37,4 = x
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= 97, 86
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Second one:

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3 years ago

Study was conducted to determine the mean birth weight of a certain breed of kittens, Consider the birth weights of kittens to b

ikadub [295]

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3 years ago

Find the perimeter of a triangle with points A(1,2), B(1,8), and C(5,5) on a Cartesian coordinate plane.

Assoli18 [71]

Check the picture below.

the distance from 1,2 to 1,8 is simply 6 units, we can read that off the grid. Now let's see what the other distances are, and add them all up to get the perimeter.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{2})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AC=\sqrt{(5-1)^2+(5-2)^2}\implies AC=\sqrt{4^2+3^2} \\\\\\ AC=\sqrt{25}\implies AC=5 \\\\[-0.35em] ~\dotfill$

$\bf B(\stackrel{x_1}{1}~,~\stackrel{y_1}{8})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) \\\\\\ BC=\sqrt{(5-1)^2+(5-8)^2}\implies BC=\sqrt{4^2+3^2} \\\\\\ BC=\sqrt{25}\implies BC=5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{perimeter}{6+5+5\implies 16}~\hfill$

7 0

3 years ago

Ty stacked some large wooden blocks. Each block is 1/3 ft tall. His stack of blocks measures 5 ft.

Oliga [24]

5 / (1/3) = 15

Ty’s stack has 15 blocks.

7 0

3 years ago

find the exepted value of the random varible with the following probability distribution x=2,3,4,5,6,7,8,9,10,11,12 Probability

dem82 [27]

The expected value of the random variable is 7

<h3>How to determine the expected value of the random variable?</h3>

The probability distribution is given as:

x=2,3,4,5,6,7,8,9,10,11,12

Probability =1/36,1/18,1/12,1/9,5/36,1/6,5/36,1/9,1/12,1/18,1/36

The expected value of the random variable is calculated using

E(X) = ∑xP(x)

Using the above formula, we have

E(x) = 2 * 1/36 + 3 * 1/18 + 4 * 1/12 + 5 * 1/9+ 6 * 5/36 + 7 * 1/6 + 8 * 5/36 + 9 * 1/9 + 10 * 1/12 + 11 * 1/18+ 12 * 1/36

Evaluate the sum of products

E(x) = 7

Hence, the expected value of the random variable is 7