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3 years ago

Brainly is useless now i get no help in hw like someone pls help

Mathematics

2 answers:

Serjik [45]3 years ago

6 0

Plug the point (-1,20) into the equation and see if it holds true.

20<1/2(-1-5)^2+2
20<1/2(-6)^2+2
20<1/2(36)+2
20<18+2
20<20
So it’s true. I left the equals sign out because I couldn’t do it on my phone. The symbol in the question is less than or equal to and it is equal so yes

olasank [31]3 years ago

4 0

SAME YOURE SO RIGHT THE ANSWE IS Y=15 i think but i’m not sure

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My question is y = 4x + 1 and my options are<br>a. 4, 3 <br>b. 4,1<br>c. 1,4<br>d. 3,1

Akimi4 [234]

Answer:

B. 4,1

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

A homeowner plans to enclose a 200 square foot rectangular playground in his garden, with one side along the boundary of his pro

tigry1 [53]

Answer:

The dimensions are 50 and 100 square foot

Step-by-step explanation:

Let x = length of fenced side parallel to the side that borders the playground

y = length of each of the other two fenced sides

Then, x + 2y = 200

<=> x = 200-2y

The Area = xy = y(200-2y)

The dimensions of the playground that will minimize the homeowner's total cost for materials when the area of the playground is maximum. He can cover more area but with the same cost.

The graph of the area function is a parabola opening downward.

The maximum area occurs when y = -200/[2(-2)] = 50

=> x = 100

So the dimensions are 50 and 100 square foot

6 0

4 years ago

(X^2+x-6)(2x^2+4x) factor completely

MissTica

Answer:

$2x\left(x-2\right)\left(x+3\right)\left(x+2\right)$

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring $x^2+x-6$ .

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For $ax^2+bx+c$ we need to find u, v > $u\cdot \:v=a\cdot \:c$ and $u+v=b$ which we will group into $\left(ax^2+ux\right)+\left(vx+c\right)$ .

The values we have are... $a=1,\:b=1,\:c=-6$ and $u\cdot v=-6,\:u+v=1$ .

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

$\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow \mathrm{False}$