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3 years ago

Determine whether y^2 = –2x – 1 is a function.

Mathematics

2 answers:

MariettaO [177]3 years ago

8 0

Answer:

It is NOT a function

Step-by-step explanation:

pychu [463]3 years ago

5 0

Y^2 = -2x - 1 is not a function

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in recent years 17.7% of households watched the finals of a popular reality series. There are 110.2 million households in the Un

prisoha [69]

17.7% x
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100% 110,200,000

If 110.2 million households equals 100%, then you just cross multiply to solve for what households are 17.7% - which is 19,505,400.

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3 years ago

Find the surface area of a regular prism iwth height 6 cm, if the base of the prism is: Equilateral triangle with a side of leng

ser-zykov [4K]

Answer:

61.8 square centimeters

Step-by-step explanation:

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3 years ago

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3 years ago

A researcher compares differences in positivity between participants in a low-, middle-, or upper-middle-class family. If she ob

777dan777 [17]

Answer:

(2, 12)

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $3$ groups and on each group from $j=1,\dots,n_j$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

The degrees of freedom for the numerator on this case is given by $df_{num}=k-1=3-1=2$ where k =3 represent the number of groups.

The degrees of freedom for the denominator on this case is given by $df_{den}=df_{between}=N-K=15-3=12$ .

And the total degrees of freedom would be $df=N-1=15 -1 =14$

And the correct answer would be 2 degrees of freedom for the numerator and 12 for the denominator

(2, 12)

3 0

3 years ago

Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and

uysha [10]

Answer:

$\frac{x^{2}}{36} - \frac{y^{2}}{64}=1$

Step-by-step explanation:

Given an hyperbola with the following conditions:

Foci at (-10,0) and (10,0)
x-intercept +/- 6;

The following holds:

The center is midway between the foci, so the center must be at (h, k) = (0, 0).

The foci are 10 units to either side of the center, so c = 10 and $c^2 = 100$
The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and $a^2 = 36.$

$Then, a^2+b^2=c^2\\b^2=100-36=64$

Therefore, substituting $a^2 = 36.$ and $b^2=64$ into the standard form

$\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1$

4 0

3 years ago