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PilotLPTM [1.2K]
3 years ago
12

Plzz answer fast guys​

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0

Answer:

z⁻⁷

Step-by-step explanation:

Use (zᵃ)ᵇ = zᵃᵇ and zᵃ * zᵇ = z⁽ᵃ⁺ᵇ⁾

Virty [35]3 years ago
3 0

Answer:

(A)

Step-by-step explanation:

ZxZ-8=

Z-7

Note* Z-8=Z in the power of - 8 and Z-7=Z in the power of - 7

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Wayne purchased 15 pounds of bird seed for $36.75 at Hank's
Sonbull [250]

Answer:

15

Step-by-step explanation:

8 0
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Help me please!!<br> hurry
zubka84 [21]

Answer:

n-3

Step-by-step explanation:

for every input, the output is three less (4-3=1, 7-3=4, 8-3=5). That rule needs to stay consistent, so no matter what the input is (n), the output is always going to be three less than, making it y or output=n-3

6 0
3 years ago
Find the coordinates of the vertices of the figure formed by each system of inequalities. x + y &lt; 9 x - 2y &lt; 12 y &lt; 2x
Vladimir [108]

Answer:

b. (10, -1), (-6, -9), (2, 7)

Step-by-step explanation:

One way to solve this problem is by graphing (see attachment). In fact, that actually is the easiest way to do this.

First, graph x + y < 9 (red part on the attachment). To do this, isolate the y so that it's like a regular linear equation: y < -x + 9. Graph the line y = -x + 9 first, and then choose a point either on the left or right of the line to plug in for x and y.

Let's just choose (0, 0), which is on the left of the line: 0 < -0 + 9  ⇒  0 < 9. Since this is a true statement, we know that we should shade the left side of the equation, and not the right side.

Now, graph x - 2y < 12 (blue part on the attachment). It's the same process here as the first inequality. For this one, we find that we also shade to the "left" of the line (it's more "up" than "left", but you get the idea).

Finally, graph y < 2x + 3 (green part on the attachment). Again, it's the same process. For this, we shade to the right.

Now look at the three points that they intersect at: they are (2, 7), (-6, -9), and (10, -1). The answer is thus B.

7 0
3 years ago
Read 2 more answers
In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
3 years ago
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