With $17.50 she can get 11 2/3 gallons. 11 (she just got) + 8 (that she had) = 19 gallons. 19 x 27 MPG = 513 Miles.
27 divided by 3 = 9 (9 is a third of the MPG) 9 x 2 (since it was 2 thirds that were left) = 18
In total she can drive 531 miles.
Answer:
<em>Results below</em>
Step-by-step explanation:
<u>Equation of the line</u>
A straight line can be written in the form:
y = ax + b
Where a and b are constants and x is the independent variable.
The essential condition for an equation to be linear is that the x must be powered to the exponent 1, which is usually not written.
From the equations presented in the table:
is linear because the exponent of the x is 1
y = 5(x+2) = 5x + 10 is linear with a=5 and b=10.
y = x is linear with a=1 and b=0
is not linear because the exponent of x is 2
is not linear because the exponent of x is 2
The table below summarizes the results
Answer:
9.2 yd
Step-by-step explanation:
Given,
hypotenuse(h)=10 yd
base(b)=4yd
perpendicular(p)=?
we have Pythagoras Theorem
h²=p²+b²
p²=h²-b²
p=(h²‐b²)½
=(10²-4²)½
=(100-16)½
=(84)½
=9.2
Answer:
y=0
Step-by-step explanation:
Find where the expression
10
x
is undefined.
x
=
0
Consider the rational function
R
(
x
)
=
a
x
n
b
x
m
where
n
is the degree of the numerator and
m
is the degree of the denominator.
1. If
n
<
m
, then the x-axis,
y
=
0
, is the horizontal asymptote.
2. If
n
=
m
, then the horizontal asymptote is the line
y
=
a
b
.
3. If
n
>
m
, then there is no horizontal asymptote (there is an oblique asymptote).
Find
n
and
m
.
n
=
0
m
=
1
Since
n
<
m
, the x-axis,
y
=
0
, is the horizontal asymptote.
y
=
0
There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes
This is the set of all asymptotes.
Vertical Asymptotes:
x
=
0
Horizontal Asymptotes:
y
=
0
No Oblique Asymptotes
image of graph
9) pi/3 = 180 /3 = 60⁰
the other angle = 90-60=30⁰
10) 2pi/9 = 360/9 = 40⁰
the other angle = 90+40=130⁰
11) arc length = 2pi * r * (θ/360)
= 2pi * 16 * (270/360)
= 75.4 km
12)arc length = 2pi * r * (θ/360)
3 * 180/4 = 135⁰
135/360 =0.375
2pi * 6 * 0.375 =14.13 in
13) arc length = 2pi * r * (θ/360)
= 9 *2pi *(255/360) =40.05 mi
14)arc length = 2pi * r * (θ/360)
=23.56 mi
