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Harman [31]
3 years ago
9

What is the name of the tide when the sun, moon, and earth are all aligned, causing the greatest pull for highest and lowest tid

es?
Question 10 options:

Low tide


Spring tide


High tide


Neap tide
Mathematics
2 answers:
Naily [24]3 years ago
7 0

Answer:

Whenever the earth, moon and sun are aligned, the gravitational pull of the moon is augmented by the gravitational pull of the sun, causing larger than average tidal ranges — meaning especially high high tides and very low low tides. These extreme tides are called “spring tides.”

Step-by-step explanation:

Deffense [45]3 years ago
3 0
The answer to your question is Spring tides
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Step-by-step explanation:

The transverse line crosses 2 parallel lines (opposite angles of a rectangle are parallel) ,  so the same side angles add up to 180 degrees.

m < A + 79 = 180

m < A = 101 degrees.

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4 apples left

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Y = -x+5y=−x+5y, equals, minus, x, plus, 5
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3 years ago
The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
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