Answer:
![\sqrt{203}](https://tex.z-dn.net/?f=%5Csqrt%7B203%7D)
Step-by-step explanation:
1. ![11^{2} + b^{2} = 18^{2}](https://tex.z-dn.net/?f=11%5E%7B2%7D%20%2B%20b%5E%7B2%7D%20%3D%2018%5E%7B2%7D)
2. ![b^{2} =203](https://tex.z-dn.net/?f=b%5E%7B2%7D%20%3D203)
3. b = ![\sqrt{203}](https://tex.z-dn.net/?f=%5Csqrt%7B203%7D)
Can't be simplified.
The cosine for ∠A is
.
Option: A.
<u>Step-by-step explanation:</u>
From the given diagram,
Opposite = 8 ft.
Adjacent = 5 ft.
In trigonometry, the formula for cosine =
.
We are not given with hypotenuse. So we have to find the hypotenuse using Pythagorean Theorem ![hypotenuse = \sqrt{opposite^2+adjacent^2}](https://tex.z-dn.net/?f=hypotenuse%20%3D%20%5Csqrt%7Bopposite%5E2%2Badjacent%5E2%7D)
.
.
hypotenuse =
.
cosine =
.
Multiply
in both numerator and denominator,
The cosine for ∠A is
.
Answer:
c. 84 time pi m squared
Step-by-step explanation:
Formula for volume of a cone: pi times radius squared times height divided by 3
for this you don't need to multiply by pi so it's
12 and radius is 6
6 squared times 7/3
36 times 7/3
83.99999
rounded to 84 time pi m squared
Answer:
Period of the given harmonic function is 1.
Step-by-step explanation:
In any harmonic function which is in the form of y = asin(bx+c) + d , we know
Period of this function will be represented as P = ![\frac{2\pi }{B}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Cpi%20%7D%7BB%7D)
Therefore for the given function d = 5 sin (2πt) we know the value of B is 2π.
So the period will be P = ![\frac{2\pi }{2\pi } = 1](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Cpi%20%7D%7B2%5Cpi%20%7D%20%3D%201)
The answer is period = 1