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2 years ago

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3х – 10 y = 14 3х - 9y = 15

1 answer:

kow [346]2 years ago

5 0

Answer:

{x,y}={8,1}Step-by-step explanation: i just looked it up

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What is the answer to this?

ch4aika [34]

Answer:

39

Step-by-step explanation:

41+x=80

x=39

5 0

3 years ago

Read 2 more answers

30 POINTS + BRAINLIEST TO FIRST CORRECT ANSWER!

Vinvika [58]

Answer:

The length will be multiplied by 2.

Step-by-step explanation:

By looking at the first and third ratio, we know that the no. of birck have been multiplied by 2 and the length has also been multiplied by 2 .

So when the number of bricks is multiplied by 2, the length is multiplied by 2

7 0

3 years ago

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There are some caps in a box. 1/6 of them are red, 1/3 are blue, and 3/7 of the remainder are green. If there are 27 green caps,

3241004551 [841]

$\frac{1}{6}x+\frac{1}{3}x+\frac{3}{7}(x-(\frac{1}{6}x+\frac{1}{3}x))=x\\\frac{3}{7}(x-(\frac{1}{6}x+\frac{1}{3}x))=27\\\frac{3}{7}(x-(\frac{1}{2}x))=27\\\frac{3}{7}(\frac{1}{2}x)=27\\x=126$

126 caps

5 0

3 years ago

Which is an extraneous solution of the exponent x+sqrtx=6

zheka24 [161]

First, we can simplify it down.
x = (-x + 6)^2
Then, you should have x - ( $x^{2}$ - 12x + 36).
Factor it to get x = 4 or 9. 4 works in the original equation but 9 does not.

3 0

3 years ago

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

<em>Step(i)</em>:-

Given differential problem

y′+3 y=9 t

<em>Take the Laplace transform of both sides of the differential equation</em>

L( y′+3 y) = L(9 t)

<em>Using Formula Transform of derivatives</em>

<em> L(y¹(t)) = s y⁻(s)-y(0)</em>

<em> By using Laplace transform formula</em>

<em> </em> $L(t) = \frac{1}{S^{2} }$ <em> </em>

<em>Step(ii):-</em>

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

<em>Step(iii</em>):-

<em>By using partial fractions , we get</em>

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

<em> B = 9/3 = 3</em>

Put s = -3 in equation(i)

9 = C(-3)²

<em>C = 1</em>

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

<em> 0 = A + C</em>

<em>put C=1 , becomes A = -1</em>

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

<u><em>Step(iv):-</em></u>

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

<em>By using inverse Laplace transform</em>

<em></em> $L^{-1} (\frac{1}{s} ) =1$ <em></em>

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

<u><em>Final answer</em></u>:-

<em>Now the solution , we get</em>

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

2 years ago