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Aleks04 [339]
3 years ago
13

Find the missing side lengths. Leave your answer as radicals in simplest form.

Mathematics
1 answer:
inn [45]3 years ago
7 0

Answer:

Solution given:

b=9 base side of isosceles triangle

a=\sqrt{9²+9²}=9\sqrt{2}

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Adding the fractions<br><br> 3/14+2/21+1/6
NARA [144]

Answer:

\frac{10}{21}

Step-by-step explanation:

The LCM of 14, 21 and 6 is 42

We require to change the fractions to fractions with a denominator of 42

\frac{3(3)}{14(3)} + \frac{2(2)}{21(2)} + \frac{1(7)}{6(7)}

= \frac{9}{42} + \frac{4}{42} + \frac{7}{42} ← add the numerators, leaving the denominator

= \frac{9+4+7}{42}

= \frac{20}{42} ← divide both values by 2

= \frac{10}{21} ← in simplest form

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you can think like this: -3-4=-1

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Step-by-step explanation:

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