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Grace [21]
3 years ago
8

True or False Rootkits are only made by black-hat hackers.

Computers and Technology
1 answer:
Kipish [7]3 years ago
4 0
True rookies are only made by black hat hackers I am not sure I hope this will help
You might be interested in
Design and implement a class Country that stores the name of the country, its population, its area, and the population density (
melomori [17]

Answer:

See explaination

Explanation:

Make use of Python programming language.

File: Country.py

class Country:

def __init__(self, n="", p=0, a=0):

""" Constructor """

self.name = n

self.population = p

self.area = a

self.pDensity = self.population / self.area

def getCountryName(self):

""" Getter method """

return self.name

def getPopulation(self):

""" Getter Method """

return self.population

def getArea(self):

""" Getter Method """

return self.area

def getPDensity(self):

""" Getter Method """

return self.pDensity

File: CountryInfo.py

from Country import *

# Opening file for reading

with open("d:\\Python\\data.txt", "r") as fp:

# List that hold countries

countryInfo = []

# Processing file line by line

for line in fp:

# Stripping spaces and new lines

line = line.strip()

# Splitting and creating object

cols = line.split('\t')

cols[1] = cols[1].replace(',', '')

cols[2] = cols[2].replace(',', '')

c = Country(cols[0], int(cols[1]), float(cols[2]))

countryInfo.append(c)

# Processing each countryInfo

largestPop = 0

largestArea = 0

largestPDensity = 0

# Iterating over list

for i in range(len(countryInfo)):

# Checking population

if countryInfo[i].getPopulation() > countryInfo[largestPop].getPopulation():

largestPop = i;

# Checking area

if countryInfo[i].getArea() > countryInfo[largestPop].getArea():

largestArea = i;

# Checking population density

if countryInfo[i].getPDensity() > countryInfo[largestPop].getPDensity():

largestPDensity = i;

print("\nLargest population: " + countryInfo[largestPop].getCountryName())

print("\nLargest area: " + countryInfo[largestArea].getCountryName())

print("\nLargest population density: " + countryInfo[largestPDensity].getCountryName() + "\n")

Please go to attachment for sample program run

4 0
3 years ago
It takes an older computer twice as long to send out a company's email as it does a newer computer. Working together, it takes t
bulgar [2K]

Answer:

13,33  MIN.

Explanation:

1. Time with Older Computer (OC) = 2 time with New Computer (NC)

2. OC+ NC = 10 MIN.

replacing 1. in 2.    OC + OC/2 = 10 min.  

1.5 OC =10min

OC=6.66 MIN

NC = 3,33 MIN.

If we replace NC with OC , 3,33 min will take 2 times (6,66 min)

Total Time = 6,66 + 6,66= 13,33 min

4 0
3 years ago
What is the output of the second println statement in the main method, public class foo { int i ; static int s ; public sttic vo
Sedaia [141]

Answer:

b) f2.i is 1 f2.s is 2

Explanation:

i is an instance variable and s is static, shared by all objects of the Foo class.

6 0
3 years ago
For a new version of processor, suppose the capacitive load remains, how much more energy will the processor consume if we incre
xxMikexx [17]

Answer:

72.80 % more energy will be consumed.

Explanation:

First of all, let us have a look at the formula of energy for a processor.

E = CV^2f

Where, E is the energy

C is the capacitance

V is the voltage and

f is the clock rate.

Let E_1 be the energy of older processor.

C_1 be the capacitance of older processor.

V_1 be the voltage of older processor

f_1 be the capacitance of older processor

So, E_1 = C_1V_1^2f_1 ....... (1)

and

Let E_2 be the energy of newer processor.

C_2 be the capacitance of newer processor.

V_2 be the voltage of newer processor

f_2 be the capacitance of newer processor

E_2 = C_2V_2^2f_2 ....... (2)

Dividing equation (2) with equation (1):

\dfrac{E_2}{E_1} = \dfrac{C_2V_2^2f_2}{C_1V_1^2f_1}

As per given statement:

C_1=C_2

V_2=1.2\times V_1

f_2=1.2\times f_1

Putting the values above:

\dfrac{E_2}{E_1} = \dfrac{C_1\times (1.2V_1)^2\times 1.2f_1}{C_1V_1^2f_1}\\\Rightarrow \dfrac{E_2}{E_1} = \dfrac{(1.2)^2\times 1.2}{1}\\\Rightarrow \dfrac{E_2}{E_1} = 1.728\\\Rightarrow \bold{E_2 = 1.728 \times E_1}

Energy consumed by newer processor is <em>1.728 </em>times the energy consumed by older processor.

OR

<em>72.80 %</em> more energy will be consumed by the newer processor.

4 0
3 years ago
Give the value of the zero flag, the carry flag, the signflag, and the overflow flag after each of the following instructions if
Vanyuwa [196]
The correct answer is A for this question
6 0
2 years ago
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