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Nadusha1986 [10]
3 years ago
13

WHATS YALL FAVORITE GAME WHOEVER GIVES THE BEST ANSWER WINS 200

Computers and Technology
2 answers:
zubka84 [21]3 years ago
4 0

Answer:

fort nite and call of duty

Explanation:

lisov135 [29]3 years ago
3 0

Answer: fornite

Explanation: 2k20

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Which of the following is NOT true about variables?
VikaD [51]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The value stored by a variable can be changed after it is assigned(true).

The value of a variable can be changed after it is assigned, for example:

int a=10;

and we can change the value of variable a in letter program such as:

a=15;

Variables are a name for a spot in the computer's memory (true).

it is true, because the variables value stored in the computer's memory and we can access theses values by their name (variable name). so Variables are a name for a spot in the computer's memory.

Variable names can be words: such as temperature or height (true).

Yes, the variable name can be words such as height, width, temperature etc.

The value stored by a variable cannot be changed after it is assigned (false).

It is noted that the value stored by a variable can be changed after it is assigned. However, it is noted that is some programming language, you can't change the value of static variable.

3 0
3 years ago
The view that perceptual processes take place over time and can be thought of in terms of a software/hardware metaphor is known
Wittaler [7]

The view that perpetual processes can be thought of in terms of a software/hardware metaphor is known as the: information processing view.

<h3>What is the Information Processing View?</h3>

Information processing view is explained by the cognitive theory to explain how the brain encodes information and how information are filtered from what we pay attention to in a particular moment. This also determines what is stored in the short-term or in our long-term memory.

Therefore, the view that perpetual processes can be thought of in terms of a software/hardware metaphor is known as the: information processing view.

Learn more about the information processing view on:

brainly.com/question/24863946

3 0
2 years ago
Does a triangle with sides of lengths 1.5 ft, 2.5 ft, and 2 ft form a right triangle? How do you know?
timama [110]

Answer:

Yes, the side lengths of 1.5, 2.5, and 2 ft form a right triangle.

Explanation:

Before we solve this problem, we need to know a couple of things.

In a right triangle, you have two legs and a diagonal line that goes from one leg to the other or from one side to the other. This line is called the hypotenuse. It is the longest side of a right triangle. This length can be calculated by using a special formula that is over a thousand years old.

The formula is called the Pythagorean Theorem.

The formula states that if you square one leg and the other leg and add it up. You get the side of hypotenuse which is squared as well.

Here it is in simple terms: a^{2} +b^{2} =c^{2}.

a and b are your two legs.

C is your hypotenuse.

In this case 1.5 and 2 are your legs and 2.5 is your hypotenuse since it is the longest side.

Before we calculate, there is a converse to the Pythagorean Theorem.

If a^{2} +b^{2} \neq c^{2}, then it is not a right triangle.

Lets make 1.5 for a

and 2 for b.

We know 2.5 is for c.

Here it is.

1.5^{2} +2^{2} =2.5^{2}. The / means it is a fraction.

1.5 squared is 9/4 and 2 squared is 4. Add 4 and 9/4 and you get 25/4 squared. Take the square root of 25/4 and you get 5/2.

5/2 is equal to 2.5, so the Pythagorean Theorem applies to this triangle. Therefore, these side lengths do form a right triangle.

Hope this helps!

3 0
3 years ago
What's the problem with this code ?
Svet_ta [14]
Hi,

I changed your program using some of the concepts you were trying to use. Hopefully you can see how it works:

#include <string>
#include <iostream>
#include <sstream>
#include <vector>
#include <algorithm>

using namespace std;

int main()
{
   short T;
   cin >> T;
   cin.ignore();

   string str[100];

   for(int i=0; i<T; i++)
   {
      getline(cin, str[i]);
   }

   for (int i = 0; i < T; i++)
   {
      stringstream ss(str[i]);
      string tmp;
      vector<string> v;

      while (ss >> tmp)
      {
          // Let's capitalize it before storing in the vector
          if (!tmp.empty())
          {
              transform(begin(tmp), end(tmp), std::begin(tmp), ::tolower);
              tmp[0] = toupper(tmp[0]);
           }
           v.push_back(tmp);
        }

        if (v.size() == 1)
        {
           cout << v[0] << endl;
        }
        else if (v.size() == 2)
        {
           cout << v[0][0] << ". "  << v[1] << endl;
        }
        else
        {
            cout << v[0][0] << ". " << v[1][0] << ". " << v[2] << endl;
        }
    }

     return 0;
}

4 0
3 years ago
Jakob is stuck in the airport on a long layover while traveling for work. He sees two Wi-Fi’s he can log onto: one says Airport
Andrei [34K]
You should pick Free Airport Wifi bc its free
3 0
3 years ago
Read 2 more answers
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