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Galina-37 [17]
3 years ago
7

In triangle PQR, the length of PQ is 5 inches and the length of PR is 9 inches. Give all the possible whole-number lengths of si

de QR.
Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0

Answer:

4

5, 6, 7, 8, 9, 10, 11, 12, and 13.

Step-by-step explanation:

We can use the triangle inequality. By the triangle inequality, the sum of any two sides of a triangle must be greater than the remaining side.

In other words, the sum of the two shorter sides must be greater than the longest side.

We know that PQ is 5 and PR is 9.

For the first case, let's say that neither PQ nor PR is the longest side. Instead, QR is the longest side. Then their sum must be greater than QR. Thus:

5+9>QR\Rightarrow QR

However, for the second case, let's say that QR is not the longest side. In this case, PR will be the longest side. Therefore, QR plus PQ must be greater than PR:

QR+5>9\Rightarrow QR>4

Thus, we have a compound inequality:

4

Therefore, the possible whole-number lengths of QR are:

5, 6, 7, 8, 9, 10, 11, 12, and 13.

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klemol [59]

Answer:

The answer is 3 3/10

Step-by-step explanation:

2 + 1/2 + 4/5

= 2 + 5/10 + 8/10

= 2 + 13/10

=2 + 1 3/10

= 3 3/10

8 0
3 years ago
What is 1.904 rounded to the nearest penny
solmaris [256]

Answer:

1.90 I believe this is the answer. Hope this helps! Have a great day!

6 0
3 years ago
Pedro bought 8 tickets to a basketball game. He paid a total of $208. Write an equation to determine whether each ticket cost $2
Kryger [21]
Here is the equation:

8x= 208

Divide both sides by 8.

x= 26

Each ticket costs 26 dollars. 

I hope this helps!
~kaikers
3 0
3 years ago
Read 2 more answers
Can you match it??. Only if you know please
Dennis_Churaev [7]

Answer:

Step-by-step explanation:

triangle: a+b>c. If two lengths are put together, and equals more than the length of the third side, then it's a triangle

right triangle: a2+b2=c2 if the square of the two lengths equal the square of the third, then it's a right triangle

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8 0
3 years ago
Ten pounds of mixed birdseed sells for 8.24 per pound. The mixture is obtained from two kinds of birdseed, with one variety pric
Kipish [7]

Answer:

2 pounds of 1st kind and 8 pounds of 2nd kind are mixed.

Explanation:

Given:

Ten pounds of mixed birdseed sells for 8.24 per pound.  

Price of the 1st variety of birdseed=5.68 per pound

Price of the 2nd variety of the birdseed=8.88 per pound.  

To find :

Pounds of 1st variety of birdseed are used in the mixture=?

Pounds of 2ndvariety of birdseed are used in the mixture=?

Solution:

Let the weight of 1st kind added in mixture be n pounds.

Then weight of 2nd kind will be 10 – n pounds.

Now, total cost of mixture = cost of 1st kind birdseed + cost of 2nd kind birdseed

Weight of mixture x cost per pound = weight of 1st kind x cost per pound + weight of 2nd kind x cost per pound.

Substituting the values,

10\times8.24 = n\times5.68 + (10-n)\times8.88

82.4 = 5.68n + 88.8 – 8.88n  

8.88n – 5.68n = 88.8 – 82.4  

3.2n = 6.4  

n = \frac{3.2}{6.4}

n = 2

Then, weight of 2nd kind is 10 – 2 = 8 pounds.

Hence, 2 pounds of 1st kind and 8 pounds of 2nd kind are mixed.

5 0
3 years ago
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