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Galina-37 [17]
3 years ago
7

In triangle PQR, the length of PQ is 5 inches and the length of PR is 9 inches. Give all the possible whole-number lengths of si

de QR.
Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0

Answer:

4

5, 6, 7, 8, 9, 10, 11, 12, and 13.

Step-by-step explanation:

We can use the triangle inequality. By the triangle inequality, the sum of any two sides of a triangle must be greater than the remaining side.

In other words, the sum of the two shorter sides must be greater than the longest side.

We know that PQ is 5 and PR is 9.

For the first case, let's say that neither PQ nor PR is the longest side. Instead, QR is the longest side. Then their sum must be greater than QR. Thus:

5+9>QR\Rightarrow QR

However, for the second case, let's say that QR is not the longest side. In this case, PR will be the longest side. Therefore, QR plus PQ must be greater than PR:

QR+5>9\Rightarrow QR>4

Thus, we have a compound inequality:

4

Therefore, the possible whole-number lengths of QR are:

5, 6, 7, 8, 9, 10, 11, 12, and 13.

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Find the area of the rectangle as a single expression.
qwelly [4]

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D) 15x^2 +6x-48

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What's the greatest common factor of 52 and 91?
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Liaaam66
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Read 2 more answers
You go shopping at a local department store with your friend and cousin. You buy one pair of jeans, four pairs of shorts, and tw
VashaNatasha [74]

Answer: Cost per pair of jeans = $ 20

Cost per pair of shorts = $12

Cost per shirt = $8

Step-by-step explanation:

Let x= cost per pair of jeans

y = Cost per pair of shorts

z= cost per shirt.

For you, total cost = x+4y+2z= 84

For your friend,  total cost = 2x+y+3z=76

For cousin, total cost = x+2y+z= 52

Required system:

x+4y+2z=84\ (i)\\ 2x+y+3z=76\ (ii)\\ x+2y+z=52\ (iii)

from (i), x=84-4y-2z    (*)

put this in (ii) and (iii) we get

2\left(84-4y-2z\right)+y+3z=76\\\Rightarrow\ -7y-z+168=76\ (iv)\\\\ 84-4y-2z+2y+z=52\\\Rightarrow\ -2y-z+84=52 \ (v)

from (iv), y=-\frac{z-92}{7}\ (vi)

\mathrm{Subsititute\:}y=-\frac{z-92}{7}\ \text{in}\ (v)

-2\left(-\frac{z-92}{7}\right)-z+84=52\\\\\Rightarrow\ -2\left(-\frac{z-92}{7}\right)-z=-32\\\\\Rightarrow\ -\frac{5z}{7}-\frac{184}{7}=-32\\\\\Rightarrow\ -5z-184=-224\\\\\Rightarrow\ -5z=-40\\\\\Rightarrow\ z=8

\mathrm{Subsititute\:}z=8\text{ in (vi)}

y=-\frac{8-92}{7}\\\\\Rightarrow \ y=12

\mathrm{Subsititute\:}z=8,\:y=12\text{ in (*)}

x=84-4\cdot \:12-2\cdot \:8\\\\\Rightarrow\ x= 20

Hence, x= 20, y= 12 , z=8

So, Cost per pair of jeans = $ 20

Cost per pair of shorts = $12

Cost per shirt = $8

7 0
3 years ago
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