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Andrews [41]
3 years ago
11

Answer the question for brainilest and 30 points

Mathematics
1 answer:
storchak [24]3 years ago
5 0
Π x 2 x 15² is not a correct expression of the volume
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Consider the following function. f(x) = 2x3 + 9x2 − 24x (a) Find the critical numbers of f. (Enter your answers as a comma-separ
viktelen [127]

Answer:

(a) The critical number of f(x) are x=-4, 1

(b)

  • Increasing for (-\infty, -4)
  • Decreasing for (-4, 1)
  • Increasing for  (1, \infty)

(c)

  • relative maximum (-4, 112)
  • relative minimum (1, -13)

Step-by-step explanation:

(a) The critical numbers of a function are given by finding the roots of the first derivative of the function or the values where the first derivative does not exist. Since the function is a polynomial, its domain and the domain of its derivatives is (-\infty, \infty). Thus:

\frac{df(x)}{dx}  = \frac{d(2x^3+9x^2-24x)}{dx} =6 x^2+18x -24\\6 x^2+18x -24=0\\\boxed{x=-4, x=1}

(b)

  • A function f(x) defined on an interval is monotone increasing on (a, b) if for every x_1, x_2 \in (a, b): x_1 implies f(x_1)
  • A function f(x) defined on an interval is monotone decreasing on (a, b) if for every x_1, x_2 \in (a, b): x_1 implies f(x_1)>f(x_2)

Combining  the domain (-\infty, \infty) with the critical numbers we have the intervals (-\infty, -4), (-4, 1) and (1, \infty). Note that any of the points are included, in the case of the infinity it is by definition and the critical number are never included because the function monotony is not defined in the critical points, i.e. it is not monotone increasing or decreasing. Now, let's check for the monotony in each interval, for this, we check for the sign of the first derivative in each interval. Evaluating in each interval the first derivative (one point is enough), we obtain the monotony of the function to be:

  • Increasing for (-\infty, -4)
  • Decreasing for (-4, 1)
  • Increasing for  (1, \infty)

(c) From the values obtained in (a) so the relative extremum are the points (-4, 112) and (1, -13). The y-values are found by evaluating the critical numbers in the original function. Since the first derivative decreases after passing through  x=-4 and increases after passing through the point x=1 we have:

  • relative maximum (-4, 112)
  • relative minimum (1, -13)

3 0
4 years ago
Hi, can someone please help me with this question!!! Thank you ☺
docker41 [41]
I think Hannah is right
6 0
3 years ago
To compute a student's Grade Point Average (GPA) for a term, the student's grades for each course are weighted by the number of
Liula [17]

Okay, here we have this:

Considering the provided information and grades, we are going to calculate the requested GPA, so we obtain the following:

Then we will substitute in the following formula:

GPA=\frac{Grades\ast Credits}{Total\text{ credits}}

Then:

\begin{gathered} GPA=\frac{3.8\cdot5+1.9\cdot2+3.0\cdot5+2.8\cdot4}{16} \\ GPA=\frac{19+3.8+15+11.2}{16} \\ GPA=\frac{49}{16} \\ GPA=3.06 \end{gathered}

Finally we obtain that the student's GPA for that term is approximately 3.06.

7 0
2 years ago
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