Hi, can someone please help me with this question!!! Thank you ☺

A coordinate grid is shown below: A coordinate grid from negative 2 to 0 to positive 2 is drawn. There are three grid lines betw

Anastasy [175]

Answer:

Part A: 0

Part B: (-1,-1) since point (-1,1) is located in quadrent four when it is reflected over the y axis the second point would be located in quadrent three and the x and y would both be negative.

Step-by-step explanation:

3 0

2 years ago

HELP APPRECIATED PLEASEEE<br> WILL GIVE BRAINLIEST !!!

kakasveta [241]

Answer:

the first line

Step-by-step explanation:

because 1.75 is almost to the number 2

hope this helps

8 0

2 years ago

A. x 1 2 3 y 1 4 9 B. x 1 2 3 y 2 5 10 C. x 1 2 3 y 3 6 9 D. x 1 2 3 y 0 3 8 Which table can be represented by a line? A) B) C)

nata0808 [166]

A.)
x y
1 1
2 4
3 9
dx=2-1→dx=1 dy=4-1→dy=3
dx=3-2→dx=1 dy=9-4→dy=5 different to 3, then this table can not be represented by a line

B.)
x y
1 2
2 5
3 10
dx=2-1→dx=1 dy=5-2→dy=3
dx=3-2→dx=1 dy=10-5→dy=5 different to 3, then this table can not be represented by a line

C.)
x y
1 3
2 6
3 9
dx=2-1→dx=1 dy=6-3→dy=3
dx=3-2→dx=1 dy=9-6→dy=3, then this table can be represented by a line

D.)
x y
1 0
2 3
3 8
dx=2-1→dx=1 dy=3-0→dy=3
dx=3-2→dx=1 dy=8-3→dy=5 different to 3, then this table can not be represented by a line

Answer: Option C. x 1 2 3 y 3 6 9

6 0

2 years ago

Suppose that 76% of Americans prefer Coke to Pepsi. A sample of 80 was taken. What is the probability that at least seventy perc

Anastasy [175]

Answer:

C. 0.896

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .