All categories

4 years ago

PLZ HELP YOU DON"T HAVE TO DO ALL BUT PLEASE SOME

Mathematics

2 answers:

Katarina [22]4 years ago

6 0

Question 1:
7/10= 0.7
71/100=0.71

Alecsey [184]4 years ago

3 0

3 it is the same
because do the division against the to decimals71.o and 9 divided by 1
2

You might be interested in

Jael has a monthly budget of x dollars. She spends $1,500 on her mortgage every month. One-fourth of her remaining budget is spe

Alecsey [184]

Answer:

B. y=(x-1500)/4

Step-by-step explanation:

Given that:

Monthly budget = x dollars

Monthly mortgage = $1500

Recreational activities = 1/4 of remaining budget

Amount in dollar spent on recreational activities =

(Monthly budget - monthly mortgage) * 1/4

(x - 1500) * 1/4

Hence,

y = (x - 1500) / 4

5 0

3 years ago

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago

What are perfect numbers between 1 and 28

snow_lady [41]

Answer:

i was trying to help u but ok delete my answer

Step-by-step explanation:

5 0

4 years ago

I need help on these what is 5=g-8

Levart [38]

The answer is g=13 I hope this helped

7 0

3 years ago

Juan rents a car for $29.00 a week. He pays $17.00 per week for the insurance and spends $13.50 weekly on gas. What will his cos

Goryan [66]

$29+$17+$13 = $59 weekly spending
So 1 month gonna be $59 times 4 = $236 per month

5 0

3 years ago

Read 2 more answers