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3 years ago

3 + (2 + 8)2 ÷ 4 × 1/ 2 to the power of 4

Mathematics

1 answer:

kicyunya [14]3 years ago

5 0

Answer:

The answer to this is 4 and 9 over 16.

Step-by-step explanation:

The expression is 3 + (2 + 8)^2 ÷ 4 × 1 over 2 to the power of 4 . it can be represented mathematically as

3 + (2 + 8)^2 ÷ 4 × (1/2)^4

using PEMDAS

parenthesis come first

3 + 10^2 ÷ 4 × (1/2)^4

exponential comes next

3 + 100 ÷ 4 × 1/16

3 + 25 × 1/16

3 + 25/16

(48 + 25)/16

73/16

4 9/16

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Malia is planting tomato and pepper plants in her garden each tomato plant t requires 6 square feet and each pepper plant p requ

MAVERICK [17]

Answer:

6 t + 4 p ≤ 150 is the required inequality.

Step-by-step explanation:

Here, the area required for 1 tomato plant = 6 sq ft

So, the area required to plant t tomato plants

= t x ( Area required by 1 tomato plant) = t x ( 6 sq ft) = 6 t

the area required for 1 pepper plant = 4 sq ft

So, the area required to plant p pepper plants

= p x ( Area required by 1 pepper plant) = p x ( 4 sq ft) = 4 p

Now, total area of the garden = 150 Sq ft.

Also, area of p pepper pants + t tomato plants = (6 t + 4 p) sq ft

So, now according to the question:

Total area of both plants ≤ Total area of the garden

⇒ (6 t + 4 p) sq ft ≤ 150 sq ft

or, 6 t + 4 p ≤ 150 is the required inequality.

5 0

3 years ago

(I WILL RATE BRAINIEST)

Umnica [9.8K]

Answer:

(a)

Shortest Side of the trapezoid =6 yds

Longest Side =8 yds

(b)42 Square Yards

Step-by-step explanation:

Part A

In the Trapezoid, Width =6 yd

Since the shortest side of the playground and its width have the same dimension, then:

Shortest Side of the trapezoid =6 yd

Longest Side =6+1+1=8 yd

Part B

Area of the Playground

In the trapezoid

a=6 yd, b=8 yd, h=Width=6 yd

Area of a trapezoid $=\frac{1}{2}(a+b)h$

$Therefore: Area=\frac{1}{2}(6+8)*6\\=14*3\\=42$ Square Yards$

7 0

3 years ago

Solve for the variable 2y-8=-3y-18

Ainat [17]

2y-8=-3y-18
5y=-10
y=-2

4 0

3 years ago

How can an expression written in either radical form or rational exponent form be rewritten to fit the other form?

adell [148]

When dealing with radicals and exponents, one must realize that fractional exponents deals directly with radicals. In that sense, sqrt(x) = x^1/2
Now, how to go about doing this:

In a fractional exponent, the numerator represents the actual exponent of the number. So, for x^2/3, the x is being squared.

For the denominator, that deals with the radical. The index, to be exact. The index describes what KIND of radical (or root) is being taken: square, cube, fourth, fifth, and so on. So, for our example x^2/3, x is squared, and that quantity is under a cube root (or a radical with a 3). Here are some more examples to help you understand a bit more:
x^6/5 = Fifth root of x^6
x^3/1 = x^3
^^^Exponential fractions still follow the same rules of simplifying, so...
x^2/4 = x^1/2 = sqrt(x)

Hope this helps!

8 0

3 years ago

PLEASE HELP QUICK

son4ous [18]

A should be the correct answer

7 0

3 years ago

Read 2 more answers