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Sonbull [250]
3 years ago
10

A ______ is the difference between the regular selling price of an item and its discounted price.

Mathematics
2 answers:
zhenek [66]3 years ago
8 0
It is sales tax, if not then try discount. I believe it would have to be one of those words
alisha [4.7K]3 years ago
6 0
I agree, sales tax or discount
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The dot plots below show the age of some dance students and some yoga students: Two dot plots are shown one below the other. The
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The yoga students

Step-by-step explanation:

This one is kinda easy but i took the test and got it right have a good day! :)

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If the area of the circle below is 18 ft2, what is the area of the shaded sector?
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The answer is B. 4.5 ft2
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Devante has a lunch account in the school cafeteria. His
AfilCa [17]

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35.50= 3x+5x+15.5

Step-by-step explanation:

6 0
3 years ago
4.
Alenkinab [10]

The statements with their relation to 0 are:

  1. Oliver owes his sister $27. \to -27
  2. A building is 38 feet tall. \to 27
  3. Erica jumped 2.7 feet above ground. \to 2.7
  4. The scuba diver was 38 feet below sea level. \to -38
  5. The basement is 8.3 feet below ground. \to -8.3

Statements that represent positions above the sea level are illustrated using the positive sign, while positions below the sea level are represented using the negative sign.

The above highlights imply that the following statements would be represented with positive sign:

  • A building is 38 feet tall.
  • Erica jumped 2.7 feet above ground.

This is so, because height and positions above the ground are above the sea level

Also, the following statements would be represented with negative sign:

  1. Oliver owes his sister $27. \to -27  
  2. The scuba diver was 38 feet below sea level. \to -38
  3. The basement is 8.3 feet below ground. \to -8.3

This is so, because debt and positions below the ground are below the sea level

Read more about positions at:

brainly.com/question/4692136

4 0
3 years ago
Approximate cos (12π/ 13) by using a linear approximation with f (x) = cos x.
Katarina [22]
First pick a value of x close to \dfrac{12\pi}{13}. You should be fine with x=\pi.

The linear approximation of f(x) at x=c is given by

f(c)\approx f(a)+f'(a)(c-a)

where x=a is some fixed value close to x=c. You have

f(x)=\cos x\implies f'(x)=-\sin x

so

f\left(\dfrac{12\pi}{13}\right)\approx f(\pi)+f'(\pi)\left(\dfrac{12\pi}{13}-\pi\right)
\cos\dfrac{12\pi}{13}\approx\cos\pi-\sin(\pi)\left(-\dfrac\pi{13}\right)
\cos\dfrac{12\pi}{13}\approx-1

The actual value is closer to -0.9709, so the approximation is decent.
4 0
3 years ago
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