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Liula [17]
3 years ago
13

Given the sample triangle below and the conditions csc B = 10, b = 0.5, find the hypotenuse of the triangle.

Mathematics
1 answer:
scZoUnD [109]3 years ago
6 0

Answer:

hey! i dont recommend putting that much points into one question, it lowers your point value meanig, you cant answer more questions than you usually can

Step-by-step explanation:

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Evaluate x/y for x equals 3/10 and y equals 4/5
Over [174]

Answer:

  x/y = 3/8

Step-by-step explanation:

y = 4/5 = 8/10, so ...

  x/y = (3/10)/(8/10) = 3/8

_____

One way to divide fractions is to make them have the same denominator. Then their ratio is the ratio of their numerators.

8 0
3 years ago
8
svetoff [14.1K]

Answer:

5+9+10+10+5+2+5+2

Step-by-step explanation:

48÷8=6

6 is median of given data

5 0
2 years ago
Read 2 more answers
Troy had 44 celery sticks on a tray for his party. He put peanut butter on 25% of the celery sticks. How many celery sticks on t
GarryVolchara [31]
Hello!

We know that any given percentage can be expressed as a fraction with a denominator of 100, as follows:

\frac{x}{100}

Because we want to find 25% of the celery sticks, we can convert this percentage into the following fraction:

\frac{25}{100} = \frac{1}{4}

Now multiply this reduced fraction by the number of celery sticks:

44 × \frac{1}{4} = \frac{44}{4}

The fraction \frac{44}{4} can be reduced to a value of 11. We have now proven that 11 celery sticks received peanut butter.

I hope this helps!
6 0
3 years ago
Pay no attention to the stuff I wrote please
pychu [463]
What's your question?
7 0
3 years ago
The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level, then the pres
seraphim [82]

Answer:

373.8mmHg

Step-by-step explanation:

a =height (in km) above sea level,

the pressure P(a) (in mmHg) is approximated given as

P(a) = 760e–0.13a .

To determine the atmospheric pressure at 5.458 km, then we will input into the equation

P(5.458km) = 760e–0.13a .

= 760e^(-0.13×5.458)

=760e^-(0.70954)

= 760×0.4919

=373.8mmHg

Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg

3 0
2 years ago
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