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Georgia [21]
3 years ago
7

The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level, then the pres

sure P(a) (in mmHg) is approximated by P(a) = 760e–0.13a . Determine the atmospheric pressure at 5.458 km
Mathematics
1 answer:
seraphim [82]3 years ago
3 0

Answer:

373.8mmHg

Step-by-step explanation:

a =height (in km) above sea level,

the pressure P(a) (in mmHg) is approximated given as

P(a) = 760e–0.13a .

To determine the atmospheric pressure at 5.458 km, then we will input into the equation

P(5.458km) = 760e–0.13a .

= 760e^(-0.13×5.458)

=760e^-(0.70954)

= 760×0.4919

=373.8mmHg

Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg

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<u>Given</u>:

The base of each triangular base is 42 m.

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The height of the triangular prism is 16 m.

We need to determine the surface area of the triangular prism.

<u>Surface area of the triangular prism:</u>

The surface area of the triangular prism can be determined using the formula,

SA=bh+(s_1+s_2+s_3)H

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Substituting the values, we get;

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The formula for calculating density is: density=mass/volume.

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