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Trava [24]
2 years ago
14

Post-Lab Question #4 Why did E have a large negative change?​

Biology
2 answers:
otez555 [7]2 years ago
8 0
It’s because E was a smaller number
aksik [14]2 years ago
6 0

Answer:

i can't answer your question

Explanation:

because not enough information wht does E stand for? can you screen shot the answer choices or screenshot the question?

hope this helps you redo your question mrk me brainliest

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For this week's CRQ, you are to design your own genetic cross between a female and a male. Be sure to include each of the follow
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Answer and Explanation:

Punnett squares are illustrations that display the product of hybrid trait crosses by genetic breeding. Established parent genotypes and phenotypes are used and are usually compatible with Mendelian ratios and inheritance. The phnomenon influencing this behaviour is the

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For this cross...

Assuming Widow's peak= dominant

<u> 1. What are the dominant and recessive traits in cross?</u>

Parent generation or P generation:

gametes: Ww → Widow's peak dominant (W), No Widow's peak recessive (w)

<u>2. Is the male homozygous dominant, homozygous recessive, or heterozygous?</u>

Heterozygousity describes the allelic makeup; these traits are made of two different forms of the same gene.

Male: Ww  →  with the W.peak;  

(Thus, with both W and w this is a heterozygous trait)

<u>3. Is the female homozygous dominant, homozygous recessive, or heterozygous?</u>

However, homozygous traits are made up of the same forms of the gene called alleles.

Female: ww → without the W.peak  

(Thus, with both w ad w this is a homozygous trait)

<u>1. genotypes and phenotypes for parent and offspring...</u>

<u></u>

Assuming heterozygousity of the male , for the cross

P generation:                          Ww× ww

                            Widow's peak  ×No Widow's peak  

F1 generation:

  • genotype:                       Ww × ww       ...(from punnet square)
  • phenotype:          2 with the W.peak; 2 without

<em>∴ 50% are genotypically heterozygous while 50% is homozygous , 2 with the W.peak; 2 without </em>

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