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qwelly [4]
3 years ago
15

Trig With Picture ASAP

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
8 0

Answer:

18

Step-by-step explanation:

V=a^3

a=∛1000=10

volume=1000 cm^3=10*10*10

one side =10 cm

to find the measure of AB (the diagonal)=10√3 =17.32

the smallest dispenser has to be greater than 17.32

the smallest amount is 18

maxonik [38]3 years ago
8 0
The answer is 18 ^^^^
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Miranda has 5/8 of a yard of ribbon. if she used 1/3 of it to make a hair bow, how much ribbon would she have left. PLEASE HELP
bezimeni [28]

Answer: 5/12

Step-by-step explanation:

Step 1

Whenever you have something OF  something, you just mulltiply.

1/3 of  5/8=  

1/3x5/8

5/24

She used 5/24, and started with 5/8

5/8-5/24= 5/12  left

8 0
1 year ago
Read 2 more answers
For g (2) = 3x – 2 find the value of x<br> -<br> for which g(x) = 10
hram777 [196]

Answer:

For g (2) = 3x -2 find the value of x

The value of x is 2

for which g(x) = 10?

10 = 3x -2

10 +2 = 3x

12 = 3x

x = 12/3

x = 4

3 0
2 years ago
Triangle EFG has coordinates E (0, 0), F (0, 2), and G (3, 0). If ΔEFG ≅ ΔXYZ, what is the measure of XY?
andreev551 [17]

Answer:

2 units

Step-by-step explanation:

Since EFG and XYZ are congruent, we can write it like this:

E = X

F = Y

G = Z

Due to E and F being two units apart on the coordinate plane, we can conclude X and Y are also at a measurement of 2 units! Hope this helps!

4 0
3 years ago
Which properties were used to simplify the following expression? Select all that apply.
Alenkinab [10]

Answer:

A P of Addition

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,
astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0
3 years ago
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