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3 years ago

Prove: 1-tan^2 x/ 1+tan^2 x= 1-sin^2 x

Mathematics

1 answer:

Bas_tet [7]3 years ago

3 0

Check solution here.hope it will be of help.

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When Noah goes bowling, his scores are normally distributed with a mean of 150 and a standard deviation of 12. What is the proba

Zarrin [17]

Answer:

The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)

Step-by-step explanation:

Given that:

Mean = μ = 150

SD = σ = 12

Let x1 be the first data point and x2 the second data point

We have to find the z-scores for both data points

x1 = 135

x2 = 167

So,

$z_1 = \frac{x_1-mean}{SD}\\= \frac{135-150}{12}\\=\frac{-15}{12}\\=-1.25$

And

$z_2 = \frac{x_2-mean}{SD}\\z_2 =\frac{167-150}{12}\\=\frac{17}{12}\\= {1.416}$

We have to find area to the left of both points then their difference to find the probability.

So,

Area to the left of z1 = 0.1056

Area to the left of z2 = 0.9207

Probability to score between 135 and 167 = z2-z1 = 0.9027-0.1056 = 0.8151

Hence,

The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)

3 0

3 years ago

Find the surface area of this triangular prism.

vesna_86 [32]

Answer:

Step-by-step explanation:

A=Area

Using the formulas

$A= 2A_{b} +(a+b+c)h\\A_{b} = \sqrt{s(s-8)(s-10)(s-6)} \\s= \frac{8+10+6}{2}$

Solving for A

$A=ah+bh+ch+\frac{1}{2}*\sqrt{-a^4+2(ab)^2+2(ac)^2-b^4+2(bc)^2-c^4}$

$A=8(2)+10(2)+6(2)+\frac{1}{2}*\sqrt{-8^{4} +2*(8*10)^{2} +2*(8*6)^{2}-10^{4} +2*(10*6)^{2}-6^{4} }$ $A=96$

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Which term describes the fraction that has a variable or a variable expression

Lilit [14]

A term that describes the fraction that has a variable or valuable expression proper factor

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Joe and grace are baking cookie

STatiana [176]

Answer:

is that a question?

Step-by-step explanation:

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ddd [48]

Answer:

$46,130,75 or $43,869.25

Step-by-step explanation:

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2 years ago