Let x% be the salt concentration of first solution.
Then in 8ml, amount of salt = 
Given that to this 8ml solution, 11ml solution of a 47% salt solution is mixed.
amount of salt in 11ml of 47% salt solution is
= 
So, total amount of salt in new mixture = 
But given that this new solution is a 43% salt solution.
Hence amount of salt in new mixture of (8+11)=19ml solution of 43% salt solution is 
Hence 
8x+517 = 817
8x=817-517 = 300
x= 300/8 = 37.5
Hence the salt concentration in the first solution is 37.5%
let the numbers be x and y
x + y = 1600 ----*
12%x = 20%y
0.12x = 0.2y
y = <u>0</u><u>.</u><u>1</u><u>2</u><u>x</u>
0.2
y = 0.6x
substitute in * eqn
x + 0.6x = 1600
1.6x = 1600
x = 1000
then,
y = 0.6*1000
y = 600
the numbers are 1000 and 600
Answer:
Range of player's height = 9 inch
Step-by-step explanation:
Given:
Number of players Height range
4 66-67
8 68 -69
14 70-71
9 72-73
1 74-75
Find:
Range of player's height
Computation:
Range = Maximum value - Minimum Value
Range of player's height = Maximum height of a player - height of a player
Range of player's height = 75 inch - 66 inch
Range of player's height = 9 inch
C - (0.40c - 0.15) - (0.60c - 0.20)
I hope this helps :)
Answer:
126°
Step-by-step explanation:
(2x +18)° = (3x)°
2x + 18 = 3x
18 = 3x - 2x
18 = x
therefore, (3x)° = (3*18)°= (54)°
