Ask question

Ask question

All categories

3 years ago

5

Help ASAP Brainliest!

2 answers:

leva [86]3 years ago

8 0

Answer:

(3,-3)

Step-by-step explanation:

torisob [31]3 years ago

3 0

3,-3 is the answer to your question

You might be interested in

7/8 and 3/4 in addition to complete the fraction box?

krok68 [10]

7/8 and 3/4
Both need to have same denominator so it would be 32, in this case because 8*4 is 32.
7/32+3/32=10/32 simplified to 5/16

3 0

3 years ago

Help help help PLEASEEEEE

AysviL [449]

Answer:

m=4b and b=4m

Step-by-step explanation:

this is the right answer

6 0

2 years ago

You had a collection of insects what ways might you classify them

Wittaler [7]

By the size , color, or if they have wings or no wings, etc. just think of what might be different on each one or group.

6 0

3 years ago

Cosθ=−2√3 , where π≤θ≤3π2 .

Alex787 [66]

Answer:

$sin(\theta + \beta) = -\frac{\sqrt{7}}{5}-4\frac{\sqrt{2}}{15}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we know that

Applying the trigonometric identity

$sin^2(\theta)+ cos^2(\theta)=1$

we have

$cos(\theta)=-\frac{\sqrt{2}}{3}$

substitute

$sin^2(\theta)+ (-\frac{\sqrt{2}}{3})^2=1$

$sin^2(\theta)+ \frac{2}{9}=1$

$sin^2(\theta)=1- \frac{2}{9}$

$sin^2(\theta)= \frac{7}{9}$

$sin(\theta)=\pm\frac{\sqrt{7}}{3}$

Remember that

π≤θ≤3π/2

so

Angle θ belong to the III Quadrant

That means ----> The sin(θ) is negative

$sin(\theta)=-\frac{\sqrt{7}}{3}$

step 2

Find the sec(β)

Applying the trigonometric identity

$tan^2(\beta)+1= sec^2(\beta)$

we have

$tan(\beta)=\frac{4}{3}$

substitute

$(\frac{4}{3})^2+1= sec^2(\beta)$

$\frac{16}{9}+1= sec^2(\beta)$

$sec^2(\beta)=\frac{25}{9}$

$sec(\beta)=\pm\frac{5}{3}$

we know

0≤β≤π/2 ----> II Quadrant

so

sec(β), sin(β) and cos(β) are positive

$sec(\beta)=\frac{5}{3}$

Remember that

$sec(\beta)=\frac{1}{cos(\beta)}$

therefore

$cos(\beta)=\frac{3}{5}$

step 3

Find the sin(β)

we know that

$tan(\beta)=\frac{sin(\beta)}{cos(\beta)}$

we have

$tan(\beta)=\frac{4}{3}$

$cos(\beta)=\frac{3}{5}$

substitute

$(4/3)=\frac{sin(\beta)}{(3/5)}$

therefore

$sin(\beta)=\frac{4}{5}$

step 4

Find sin(θ+β)

we know that

$sin(A + B) = sin A cos B + cos A sin B$

so

In this problem

$sin(\theta + \beta) = sin(\theta)cos(\beta)+ cos(\theta)sin (\beta)$

we have

$sin(\theta)=-\frac{\sqrt{7}}{3}$

$cos(\theta)=-\frac{\sqrt{2}}{3}$

$sin(\beta)=\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute the given values in the formula

$sin(\theta + \beta) = (-\frac{\sqrt{7}}{3})(\frac{3}{5})+ (-\frac{\sqrt{2}}{3})(\frac{4}{5})$

$sin(\theta + \beta) = (-3\frac{\sqrt{7}}{15})+ (-4\frac{\sqrt{2}}{15})$

$sin(\theta + \beta) = -\frac{\sqrt{7}}{5}-4\frac{\sqrt{2}}{15}$

8 0

3 years ago

NEED HELP ASAP PLEASE

timurjin [86]

If the unknown value is x, then x = $\frac{14}{4}$ × 6 = 21.

Explanation:

Since it is a double number line with a ratio, all the ratios of one number line to the other will remain equal for all the values along both the number lines. Assume the unknown value to be x.
The ratio of the number on the first number line to the corresponding number on the second number line is calculated to be; $\frac{7}{2}$ = $\frac{14}{4}$ = $\frac{x}{6}$ = $\frac{28}{8}$ = $\frac{35}{10}$ = 3.5. So $\frac{x}{6}$ = 3.5, x = 3.5 × 6 = 21.
We can also calculate x by the following method. As ratios are equal we can directly substitute the value to another ration. So $\frac{14}{4}$ = $\frac{x}{6}$ , x = $\frac{14}{4}$ × 6 = $\frac{84}{4}$ = 21.

3 0

3 years ago

Read 2 more answers