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SIZIF [17.4K]
3 years ago
10

What is m∠B?A.51B..129C.134D.141

Mathematics
1 answer:
san4es73 [151]3 years ago
7 0

Answer:

I think it 129 If not try 4

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Find the APY for an APR of 3.6% compounded (a) yearly. (b) semi-annually. (c) monthly. (d) continuously.
madam [21]

Answer:

Monthly

Step-by-step explanation:

APY is 0.0302 = 3.02 Percent - 3.00% - monthly

5 0
2 years ago
Tim is investigating the relationship between the number of years since a tree was planted and the height of the tree in feet. H
wolverine [178]

Answer: There is not a good prediction for the height of the tree when it is 100 years old because the prediction given by the trend line produced by the regression calculator probably is not valid that far in the future.

Step-by-step explanation:

Years since tree was planted (x) - - - - height (y)

2 - - - - 17

3 - - - - 25

5 - - - 42

6 - - - - 47

7 - - - 54

9 - - - 69

Using a regression calculator :

The height of tree can be modeled by the equation : ŷ = 7.36X + 3.08

With y being the predicted variable; 7.36 being the slope and 3.08 as the intercept.

X is the independent variable which is used in calculating the value of y.

Predicted height when years since tree was planted(x) = 100

ŷ = 7.36X + 3.08

ŷ = 7.36(100) + 3.08

y = 736 + 3.08

y = 739.08

Forward prediction of 100 years produced by the trendline would probably give an invalid value because the trendline only models a range of 9 years prediction. However, a linear regression equation isn't the best for making prediction that far in into the future.

3 0
3 years ago
What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9
weeeeeb [17]

The difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

<h3>How to determine the difference?</h3>

The expression is given as:

\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}

Factor the denominators of the expressions:

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}

Apply the difference of two squares to x² - 9

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}

Take LCM

\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Hence, the difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Read more about expressions at:

brainly.com/question/723406

#SPJ4

6 0
2 years ago
The mean score on biology quiz was 62 with a standard deviation of 8, Jose’s score was a 74% what was his z score?
melisa1 [442]
(74-62)/8=3/2=1.5
Thank you hope this helps
7 0
2 years ago
Can you explain algebra
julia-pushkina [17]
Hell. fire blazing. pure hell<3
6 0
2 years ago
Read 2 more answers
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