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Virty [35]
4 years ago
9

How do you factor 18x+6y using gcf

Mathematics
1 answer:
maw [93]4 years ago
7 0
Take out the largest common number
In this case is 6

6(3x + y)

hope this helps

you can factor 6 out of both
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Find the value of the angle θ rounded to 1 DP.<br><br> The diagram is not drawn accurately
ollegr [7]

Answer:

Find length opposite to 30deg

Opposite = tan(30)*42

= 24.2

Whole side = 24.2+10

Find angle of 0 + 30deg: (say x)

Tan(x) = 33.2/42

Arctan(0.79) = x

x = 38.3

The angle to find:

38.3-30:

8.3

The angle is 8.3deg.

8 0
3 years ago
A car travels 3 miles in 4 minutes. At this rate, how many miles does the car travel in one hour?
natima [27]

Answer:

3 miles= 4 minutes

? miles=60 minutes

<u>3 x 60</u>

  4

=45 miles

Step-by-step explanation:

7 0
3 years ago
Need help asap please
il63 [147K]

Answer:

\displaystyle 77

Step-by-step explanation:

Isosceles triangles will always tell you what you need to know. All angles are congruent, therefore all edges are congruent. ‍♂️

I am joyous to assist you at any time.

8 0
3 years ago
Triangle ABC has vertices at (-3, -1), (-1, 2) and (6, 1). What is the perimeter of triangle ABC, rounded to the nearest tenth?
Marta_Voda [28]

Perimeter=19.9units

Why?

We can find the perimeter of any triangle adding the length of its sides. Since we are given 3 points, we need to calculate the length of the three sides of the triangle,  and then add them to know the perimeter of the triangle.

Let be the points:

A(-3,-1)

B(-1,2)

C(6,1)

<h3>- Distances</h3>

From A to B:

d(A,B)=\sqrt{(-1-(-3))^{2}+(2-(-1)^{2}}\\\\d(A,B)=\sqrt{(2)^{2}+(3)^{2}}=\sqrt{4+9}=3.61units

From A to C:

d(A,C)=\sqrt{6-(-3))^{2}+(1-(-1)^{2}}\\\\d(A,B)=\sqrt{(9)^{2}+(2)^{2}}=\sqrt{81+4}=9.22units

From B to C:

d(B,C)=\sqrt{6-(-1))^{2}+(1-2)^{2}}\\\\d(A,B)=\sqrt{(7)^{2}+(-1)^{2}}=\sqrt{49+1}=7.07units

Now, calculating the perimeter, we have:

Perimeter=d(A,B)+d(A,C)+d(B,C)=3.61units+9.22units+7.07units\\\\Perimeter=19.9units

Have a nice day!

5 0
3 years ago
Given: <br> PQ<br> ⊥<br> QR<br> , PR=20,<br> SR=11, QS=5<br> Find: The value of PS.
dlinn [17]

Answer:

The value of the side PS is 26 approx.

Step-by-step explanation:

In this question we have two right triangles. Triangle PQR and Triangle PQS.

Where S is some point on the line segment QR.

Given:

PR = 20

SR = 11

QS = 5

We know that QR = QS + SR

QR = 11 + 5

QR = 16

Now triangle PQR has one unknown side PQ which in its base.

Finding PQ:

Using Pythagoras theorem for the right angled triangle PQR.

PR² = PQ² + QR²

PQ = √(PR² - QR²)

PQ = √(20²+16²)

PQ = √656

PQ = 4√41

Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.

Finding PS:

Using Pythagoras theorem, we have:

PS² = PQ² + QS²

PS² = 656 + 25

PS² = 681

PS = 26.09

PS = 26

7 0
3 years ago
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