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Verizon [17]
2 years ago
14

How did you find each square root? ​

Mathematics
1 answer:
AnnZ [28]2 years ago
8 0

Answer:

......

Step-by-step explanation:

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3 years ago
☆pls help no one has helped me and I'm so confused! ​
motikmotik

Answer:

Step-by-step explanation:

a). \frac{5\pm\sqrt{-4}}{3} = \frac{5}{3}\pm \frac{\sqrt{-4}}{3}

               = \frac{5}{3}\pm\frac{2\sqrt{(-1)} }{3}

               = \frac{5}{3}\pm\frac{2i}{3} [Since, i = \sqrt{(-1)}]

b). \frac{10\pm\sqrt{-16}}{2} = \frac{10}{2}\pm \frac{\sqrt{-16}}{2}

                  = 5\pm \frac{4\sqrt{-1}}{2}

                  = 5 ± 2i [Since, i = \sqrt{(-1)}]

c). \frac{-3\pm \sqrt{-144}}{6} = -\frac{3}{6}\pm \frac{\sqrt{-144}}{6}

                    = -\frac{3}{6}\pm \frac{12\sqrt{-1}}{6}

                    = -\frac{1}{2}\pm 2\sqrt{-1}

                    = -\frac{1}{2}\pm 2i [Since, i = \sqrt{(-1)}]

4 0
2 years ago
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Answer:

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Step-by-step explanation:

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