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avanturin [10]
2 years ago
9

7th grade math help me plzzzz

Mathematics
2 answers:
Anettt [7]2 years ago
4 0

Answer:

the answer is 161

Step-by-step explanation:

......

natka813 [3]2 years ago
4 0

Answer:

the answer would be 161

Step-by-step explanation:

Thank you come again

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How would you compare the radius of a circle with the circle diameter?
Masja [62]

Answer:

The radius is always half of the diameter.

Step-by-step explanation:

4 0
3 years ago
A<br> Find the value of x. Your answer must be exact.<br> 30<br> 9
OLEGan [10]
Tan30=9/x so it will be 9((3)^1/2)
4 0
3 years ago
Read 2 more answers
Given the system of equations:
uranmaximum [27]

Answer:

x=4

y=2

Step-by-step explanation:

2x+2y=12

x−y=2

​In order to solve by elimination, coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other.

2x+2y=12,x−y=2

To make 2x and x equal, multiply all terms on each side of the first equation by 1 and all terms on each side of the second by 2.

2x+2y=12,2x+2(−1)y=2×2

Simplify.

2x+2y=12,2x−2y=4

Subtract 2x−2y=4 from 2x+2y=12 by subtracting like terms on each side of the equal sign.

2x−2x+2y+2y=12−4

Add 2x to −2x. Terms 2x and −2x cancel out, leaving an equation with only one variable that can be solved.

2y+2y=12−4

Add 2y to 2y.

4y=12−4

Add 12 to −4.

4y=8

Divide both sides by 4.

y=2

Substitute 2 for y in x−y=2. Because the resulting equation contains only one variable, you can solve for x directly.

x−2=2

Add 2 to both sides of the equation.

x=4

The system is now solved.

x=4,y=2

Correct choice is B) x=4.

8 0
2 years ago
Read 2 more answers
PLEASSSE HELP ASAP PRETTY PLEASEEEEEEE
CaHeK987 [17]

Answer:

Third option. I am sure it!

Step-by-step explanation:

Mark other guy brainliest. He's a great answer and he helped me before

6 0
3 years ago
Read 2 more answers
. Andrew made an error in determining the polynomial equation of smallest degree whose roots are 3, 2+2i
KIM [24]

Answer:

Error of Andrew: Made incorrect factors from the roots

Step-by-step explanation:

Roots of the polynomial are: 3, 2 + 2i, 2 - 2i. According to the factor theorem, if a is a root of the polynomial P(x), then (x - a) is  a factor of P(x). According to this definition:

(x - 3) , (x - (2 + 2i)) , (x - (2 - 2i)) are factors of the required polynomial.

Simplifying the brackets, we get:

(x - 3), (x - 2 - 2i), (x - 2 + 2i) are factors of the required polynomial.

This is the step where Andrew made the error. The factors will always be of the form (x - a) , not (x + a). Andrew wrote the complex factors in form of (x + a)  which resulted in the wrong answer.

So, the polynomial would be:

(x - 3)(x - 2 - 2i)(x - 2+2i)=0\\\\ (x-3)(x^{2}-2x+2xi-2x+4-4i-2xi+4i-4i^{2})=0\\\\ (x-3)(x^{2}-4x+4+4)=0\\\\ (x-3)(x^{2}-4x+8)=0\\\\ x^{3}-4x^{2}+8x-3x^{2}+12x-24=0\\\\ x^{3}-7x^{2}+20x-24=0

7 0
3 years ago
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