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3 years ago

Which series of transformations will not map figure H onto itself?

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

3 0

Answer:

(x + 0, y − 2), reflection over y = 1

Step-by-step explanation:

H will be shifted down 2 units and then reflected over y = 1, which maps H into itself

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2 years ago

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Match each graph with the correct slope of the line. drag and drop the answer

OLEGan [10]

Answer/Step-by-step explanation:

✔️Slope of the first graph:

Using two points on the line, (0, 1) and (3, 2),

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 1}{3 - 0} = \frac{1}{3}$

Slope = ⅓

✔️Slope of the second graph:

Using two points on the line, (0, 0) and (1, 1),

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 0}{1 - 0} = \frac{1}{1} = 1$

Slope = 1

✔️Slope of the third graph:

Using two points on the line, (0, 1) and (2, 2),

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 1}{2 - 0} = \frac{1}{2}$

Slope = ½

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3 years ago

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How many ounces are in a 12 lb bag of potatoes

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3 years ago

Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centere

Ket [755]

Answer:

$e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...$

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

Step-by-step explanation:

<u>Taylor series</u> expansions of f(x) at the point x = a

$\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...$

This expansion is valid only if $\text{f}\:^{(n)}(a)$ exists and is finite for all $n \in \mathbb{N}$ , and for values of x for which the infinite series converges.

$\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1$

$\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...$

$\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}$