Answer:
1/4.
Explanation:
The autosomal dominant trait means that the trait is visible in homozygous dominant and in heterozygous condition. The X linked recessive trait will be pass down from mothers to their sons and daughters will show the trait in homozygous recessive condition only.
The man is achandroplastic dwarf ( Aa) with normal vision (XY ) is married with woman that has normal height (aa) with color blind (XhXh). They have a daughter who is dwarf ( Aa). The probability of being dwarf can be calculated by the cross Aa × aa. The offspring are Aa, Aa, aa, aa. Means 1/2 are the probability of being hetterozygous for achondroplastic . The vision probability is calculated by cross XY and XhXHh. The probability that female is heterozygous is 1/2.
So, the heterozygous probability for both trait is 1/2× 1/2 = 1/4.
Answer:
To allow simultaneous replication of the leading and lagging strands by dimeric DNA pol III, the DNA of the leading strand has to be folded.
This is false.
Explanation:
I hope that helps. I don't know if it right or wrong, but good luck :)
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