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REY [17]
3 years ago
15

Michelle made 26 more sales calls last month than Allen. Together, they made 120 calls. How many calls were made by Michelle?

Mathematics
1 answer:
algol133 years ago
6 0

Answer

73

Step-by-step explanation:

you need to subtract the 26 from 120 to get 94 divide that by 2 to get 47 so thats haw many calls they each made then add on the 26 to find her amount to get 73

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Please Help!!
GarryVolchara [31]

Answer:

D:) (2,2,) is the Answer

Step-by-step explanation:

Solve the following system:


{X - 2 Y = -2 | (equation 1)


{3 X - 2 Y = 2 | (equation 2)



Swap equation 1 with equation 2:


{3 X - 2 Y = 2 | (equation 1)


{X - 2 Y = -2 | (equation 2)



Subtract 1/3 × (equation 1) from equation 2:


{3 X - 2 Y = 2 | (equation 1)


{0 X - (4 Y)/3 = (-8)/3 | (equation 2)



Multiply equation 2 by -3/4:


{3 X - 2 Y = 2 | (equation 1)


{0 X+Y = 2 | (equation 2)



Add 2 × (equation 2) to equation 1:


{3 X+0 Y = 6 | (equation 1)


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Divide equation 1 by 3:


{X+0 Y = 2 | (equation 1)


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Collect results:


Answer:  {X = 2 , Y = 2

4 0
3 years ago
Read 2 more answers
19 4/12 + 17 2/11 - 16 6/9 =
SOVA2 [1]

Answer:

19 28/33

Step-by-step explanation:

lets work out the whole number parts first:

= 19 + 17 - 16 = 20.

4/12 + 2/11 - 6/9

= 1/3 + 2/11 - 6/9

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3 = 3

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9 = 3*3

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So we have:

33/99 + 18/99 - 66/99

= 51/99 - 66/99

= -15/99

= -5/33

So the answer is  20 - 5/33

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You just had to subtract 5/33 from 20.

6 0
3 years ago
Solve this equation. 5n+7=7(n+1)-2n
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5n + 7 = 7n - 2n + 7

5n + 7 = 5n + 7

If you want to solve for n, subtract 7 from both sides

5n + 7 (-7) = 5n + 7 (-7)

5n = 5n

then divide 5 from both sides

5n/5 = 5n/5

n = n

Effectively, this equation is <em>unsolvable</em>

hope this helps
3 0
3 years ago
Read 2 more answers
44.64 divided by 48​
Alik [6]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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If the atomic number is 15 how many protons will it have?
andrey2020 [161]
It will have 15 protons because the atomic number will always equal the number of protons and vice versa
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