In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.
1 answer:
Answer:
21.9°
Step-by-step explanation:
In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.
We solve this above question using the Sine rule
a/sin A = b/sin B
In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet.
Hence:
HI/∠J = JH/∠H
= 8/sin 90° = 1.9/sin ∠H
Cross Multiply
∠H = arc sin(sin 1.9 × 90/8)
∠H = 21.9°
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