In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.

Mathematics

1 answer:

artcher [175]2 years ago

5 0

Answer:

21.9°

Step-by-step explanation:

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.

We solve this above question using the Sine rule

a/sin A = b/sin B

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet.

Hence:

HI/∠J = JH/∠H

= 8/sin 90° = 1.9/sin ∠H

Cross Multiply

∠H = arc sin(sin 1.9 × 90/8)

∠H = 21.9°

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