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Hitman42 [59]
3 years ago
12

Would it be easier for Dana from problem 3-68 to find a single 12-foot board of clear wood rather than four clear 3-foot pieces?

Use a simulation to estimate the average number of 12-foot boards he would have to consider.
Mathematics
1 answer:
Tanzania [10]3 years ago
8 0
Yes Dana is correct because he is black and it’s Black Lives Matter month
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Find a, b, and <br><br>plz help me and don't spam me with links ​
Natali5045456 [20]
A° = 38, b°= 90, c° = 38


the square on the angle opposite to b shows that it is a right angle which means it’s 90°
5 0
3 years ago
The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand
Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                         P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean strength of 50 items = 74.28

            \sigma = population standard deviation = 2.15

            n = sample of items = 50

            \mu = population mean tensile strength after machine was adjusted

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                  significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                 = [ 74.28-1.96 \times {\frac{2.15}{\sqrt{50} } } , 74.28+1.96 \times {\frac{2.15}{\sqrt{50} } } ]

                 = [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

<em>Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.</em>

8 0
3 years ago
SQUARE ROOT OF 16<br><br>THANKS​
Mila [183]

Answer:

4

Step-by-step explanation:

FAQs on the Square Root of 16

The square root of 16 is 4.

8 0
2 years ago
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HELP NEED TO GRADUATE SO I NEED TO FINISH THIS FLVS
Mademuasel [1]
The answer is B :)

Hope this helped :)
4 0
3 years ago
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33) Given the graphs of f(x) = x - 1 and g(x) = -x - 7, what is the solution to the equation f(x) = g(x)?
neonofarm [45]

Answer:

B

Step-by-step explanation:

The solution is the point of intersection of the 2 lines

The lines intersect at (- 3, - 4 ), then

f(x) = g(x) has solution x = - 3

6 0
2 years ago
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