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Xelga [282]
3 years ago
9

There are 8 circles and 6 squares. what is the simplest ratio of squares to circles?

Mathematics
1 answer:
Ierofanga [76]3 years ago
6 0

Answer:

4:3

Step-by-step explanation:

Given function:

  • 8 circle by 6 squares

Divide similar factor by each term:

  • 8=4·2
  • 6=3·2

Rewrite:

  • 4:3

Therefore, the simplest ratio for 8 circles and 6 squares would be 4:3..

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Ulleksa [173]

Range I think I may be wrong ?

6 0
3 years ago
The scale of a map is 2 cm : 21 km. find the actual distance for 9 cm on the map.
DIA [1.3K]
I hope this helps you

if 2 cm 21 km

9cm ? km

?×2=9×21

?=189÷2

?=94,5 km
8 0
3 years ago
Read 2 more answers
These two trapezoids are similar What is the correct way to complete the similarity statement?
pentagon [3]

Option A:

\mathrm{ABCD} \sim \mathrm{GFHE}

Solution:

ABCD and EGFH are two trapezoids.

To determine the correct way to tell the two trapezoids are similar.

Option A: \mathrm{ABCD} \sim \mathrm{GFHE}

AB = GF (side)

BC = FH (side)

CD = HE (side)

DA = EG (side)

So, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

Option B: \mathrm{ABCD} \sim \mathrm{EGFH}

In the given image length of AB ≠ EG.

So, \mathrm{ABCD} \sim \mathrm{EGFH} is the not the correct way to complete the statement.

Option C: \mathrm{ABCD} \sim \mathrm{FHEG}

In the given image length of AB ≠ FH.

So, \mathrm{ABCD} \sim \mathrm{FHEG} is the not the correct way to complete the statement.

Option D: \mathrm{ABCD} \sim \mathrm{HEGF}

In the given image length of AB ≠ HE.

So, \mathrm{ABCD} \sim \mathrm{HEGF} is the not the correct way to complete the statement.

Hence, \mathrm{ABCD} \sim \mathrm{GFHE} is the correct way to complete the statement.

3 0
2 years ago
Find p(2) and p(4) for the function p(x) = 6x4 + 4x3 – 3x2 + 8x + 15.
gulaghasi [49]

Answer:

p(2) =147 and p(4) = 1791

Step-by-step explanation:

We are given p(x)= 6x^4 + 4x^3 – 3x^2 + 8x + 15.

Now we need to find value of p(2) and p(4)

Put x =2,

p(2) = 6(2)^4 + 4(2)^3 – 3(2)^2 + 8(2) + 15

p(2) = 6(16)+4(8)-3(4)+8(2)+15

p(2) = 96+32-12+16+15

p(2) = 147

Now put x = 4

p(4) = 6(4)^4 + 4(4)^3 – 3(4)^2 + 8(4) + 15

p(4) = 6(256)+4(64)-3(16)+8(4)+15

p(4) = 1536+256-48+32+15

p(4) = 1791

3 0
3 years ago
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Put Them in The box They Go in
pav-90 [236]

Answer:

\frac{1}{3}  \times r - 4 \\ 3 \times r - 4 \\  \frac{1}{3}  \times r + 4 \\ 3(r + 4)

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