Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
So 9% of 13 is 1.17
so then you go $13 - $1.17 and your answer is $11.83
Answer:
80in3
Step-by-step explanation:
12 x 4 = 48
48 / 2 = 24
24 x 10 =240
240 / 3 = 80
So your answer is 80in3
Answer:
31%
Step-by-step explanation:
100- 75 = 25
25/81 = 0.308 = 31%
Answer: ![\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B2%7D)
Step-by-step explanation:
You know that the expression is ![\frac{\sqrt{2}}{\sqrt[3]{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D)
By definition we know that:
![\sqrt[n]{a}=a^{\frac{1}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D)
You also need to remember the Quotient of powers property:

Therefore, you can rewrite the expression:

Finally, you have to simplify the expression. Therefore, you get:
![=2^{(\frac{1}{2}-\frac{1}{3})}\\=2^{\frac{1}{6}}\\=\sqrt[6]{2}](https://tex.z-dn.net/?f=%3D2%5E%7B%28%5Cfrac%7B1%7D%7B2%7D-%5Cfrac%7B1%7D%7B3%7D%29%7D%5C%5C%3D2%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%5C%5C%3D%5Csqrt%5B6%5D%7B2%7D)