Answer:
184
Step-by-step explanation:
The sqrt(144) = 12
14^2 = 196
196 - 12 - 184
1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,
A = L*H = 12*6 = 72 cm^2
3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).
Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2
4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.
Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
For this case we must find the solution of the following equation:
Applying distributive property on the right side of the equation we have:
Subtracting 7x from both sides of the equation:
Subtracting 20 from both sides of the equation:
Different signs are subtracted and the major sign is placed.
Dividing between -2 on both sides of the equation:
Thus, the solution of the equation is
Answer:
Answer:
domain = 0 < x < infinity / range = y < 4
Step-by-step explanation:
