All categories

2 years ago

Il give brainliest to correct answer

Mathematics

1 answer:

Len [333]2 years ago

3 0

Answer:

x=18

Step-by-step explanation:

brainliest?

You might be interested in

in a given year, the rate of flu infection for the general public was 8.3%. And sample of 200 people who receive the flu vaccine

makkiz [27]

Answer:

$\fbox{\begin{minipage}{10em}Option A is correct\end{minipage}}$

Step-by-step explanation:

Step 1: Define significance level

In this hypothesis testing problem, significance levels α is selected: $0.05$ , the associated z-value from Laplace table:

Φ( $z$ ) = α - $0.5 = 0.05 - 0.5 = -0.45$

=> $z$ = $-1.645$

Step 2: Define null hypothesis ( $H_{0}$ ) and alternative hypothesis ( $H_{1}$ )

$H_{0}$ : rate of flu infection $p$ = 8.3% or 8.3/100 = 0.083

$H_{1}$ : rate of flu infection $p$ < 8.3% or 8.3/100 = 0.083

Step 3: Apply the formula to check test statistic:

$K = \frac{f - p}{\sqrt{p(1 - p)} } * \sqrt{n}$

with $f$ is actual sampling percent, $p$ is rate of flu infection of $H_{0}$ , $n$ is number of samples.

The null hypothesis will be rejected if $K < z$

Step 4: Calculate the value of K and compare with $z$

$K = \frac{(\frac{3.5}{100}) - 0.083}{\sqrt{0.083(1 - 0.083)} } * \sqrt{200} = -2.46$

We have $-2.46 < -1.645$

=>This is good evidence to reject null hypothesis.

=> The actual rate is lower. (As $H_{1}$ states)

Hope this helps!

5 0

2 years ago

How are √25 and √-25 different in the terms of a solution for both? *

Tanya [424]

Answer:

For $\sqrt{25}$ it will be plus or minus $\sqrt{5}$

For $\sqrt{-25}$ it will be plus or minus $\sqrt{5i}$

Step-by-step explanation:

Well for $\sqrt{-25}$ it will be 5i

Because i = -1

6 0

2 years ago

If m 1 = 140 and m 3 = 50, what is m 5

dolphi86 [110]

The answer is: m5 = -40.

7 0

3 years ago

Read 2 more answers

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$