If (x+2) is a factor of x^3-6x^2+kx+10, k=

1 answer:

3 0

If a binomial $(x-a)$ is a factor of a polynomial, then $a$ is a root of this polynomial.

$(x+2)=(x-(-2)) \Rightarrow a=-2\\\\
(-2)^3-6\cdot(-2)^2+k\cdot(-2)+10=0\\
-8-24-2k+10=0\\
-2k=22\\\
\boxed{k=-11}
$

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Step-by-step explanation:

First, find the value of x. To find the value of x, derive an equation which you'd use in solving for x.

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