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2 years ago

Please need help fast thank you. The problem is in the picture.

Mathematics

2 answers:

Pachacha [2.7K]2 years ago

8 0

Answer:

Step-by-step explanation:

∠1 , ∠4 and ∠8

ioda2 years ago

6 0

Angles one and four are congruent with angle 5

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A total of 70 tickets were sold for a concert and earn the organizers $804. If the cost of each ticket is either $10 or $12, how

crimeas [40]

Answer:

52 tickets cost $10 and 18 tickets cost $12

Step-by-step explanation:

10x+12y=804. (1)

x+y=70. (2)

From (2)

x=70-y

Substitute x=70-y into (1)

10x+12y=804

10(70-y)+12y=804

700-10y+12y=804

700+2y=804

2y=804-700

2y=104

y=104/2

y=52

Recall

x+y=70

x+52=70

x=70-52

x=18

52 tickets cost $10 and 18 tickets cost $12

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3 years ago

Identify the solution of the inequality |4x − 2| > 14 and the graph that represents it.

kodGreya [7K]

The solution to the inequality |4x − 2| > 14 is x > 4 and x < -3

<h3>What is an inequality?</h3>

An inequality is an expression that shows the non equal comparison of two or more numbers and variables.

Given the inequality:

|4x − 2| > 14

Hence:

4x - 2 > 14 or -(4x - 2) > 14

x > 4 or x < -3

The solution to the inequality |4x − 2| > 14 is x > 4 and x < -3

Find out more on inequality at: brainly.com/question/24372553

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2 years ago

• What Were the Headlines After a 3 Foot 10 Inch Fortuneteller

pogonyaev

I have no idea what it is lol

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3 years ago

Pls HELP!! it is factoring PST answer with explanation please!!!!!! 30 points!

kondaur [170]

Step-by-step explanation:

these are the answers of your questions

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2 years ago

Read 2 more answers

The general form of an parabola is 2x2−12x−3y+12=0 .

Murljashka [212]

Answer:

The standard form of the parabola is $(x-3)^2=4*\frac{3}{8}(y+2)$

Step-by-step explanation:

The standard form of a parabola is

$(x-h)^2=4p(y-k)$ .

In order to convert $2x^2-12x-3y+12=0$ into the standard form, we first separate the variables:

$2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y$

we now divided both sides by 2 to remove the coefficient from $2x^2$ and get:

$x^2-6x+6=\frac{3}{2}y$ .

We complete the square on the left side by adding 3 to both sides:

$x^2-6x+6+3=\frac{3}{2}y+3$

$x^2-6x+9=\frac{3}{2}y+3$

$(x-3)^2=\frac{3}{2}y+3$

now we bring the right side into the form $4p(y-k)$ by first multiplying the equation by $\frac{2}{3}$ :

$\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2$

and then we multiplying both sides by $\frac{3}{2}$ to get

$(x-3)^2=\frac{3}{2} (y+2)$ .

Here we see that

$4p=\frac{3}{2}$

$\therefore p=\frac{3}{8}$

Thus, finally we have the equation of the parabola in the standard form:

$\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}$

5 0

3 years ago