Answer:
- Infinitely many solutions
Step-by-step explanation:
First, let's organize the equations of the lines into slope-intercept form.
- x + 4y = 1
- => 4y = -x + 1
- => y = -x/4 + 1/4
And,
- 2x + 8y = 2
- => 8y = -2x + 2
- => y = -2x/8 + 2/8
- => y = -x/4 + 1/4
Since both the graphs are the same, the two equations have infinitely many solutions.
Answer:
The correct answer is <u>-14</u>
Step-by-step explanation:
Okay so, togo flies 30 miles in 3/5 of an hour with the wind.togo flies 30 miles in 5/6 of an hour against the wind. his rate of speed with the wind was 30 / (3/5) = 30*5/3 = 150/3 = 50 mph.his rate of speed against the wind was 30 / (5/6) = 30*6/5 = 6*6 = 36 mph.3/5 of an hour times 50 mph = 30 miles.
5/6 of an hour times 36 mph = 30 miles.mph looks good.
going he was with the wind.
his rate of speed then was the airplane speed plus the wind speed.coming back he was against the wind.his rate of speed then was the airplane speed minus the wind speed.-----50 mph = A + W36 mph = A - W-----looks like A + W - (A - W) should equal 50 - 36.removing parentheses, equation becomesA + W - A + W = 14.
combining like terms, the equation becomes2*W = 14.dividing both sides by 2, equation becomesW = 7.if W = 7, then A can be found as follows:50 = A + 7A = 43.likewise,36 = A - 7A = 43.since the airplane speed is the same, it looks like the answer is good.solving in the original equations, we get3/5 * (43 + 7) = 303/5 * 50- = 3030 = 30good.-----5/6 * (43 - 7) = 305/6 * 36 = 3030 = 30good.
answer is W = 7 and A = 43.
20 * 15 * 10 *10^-6
= 0.003
Answer:
tanΘ = - 
Step-by-step explanation:
Using the trigonometric identity
tan²Θ + 1 = sec²Θ, thus
tan²Θ + 1 = (
)² = 
( subtract 1 from both sides )
tan²Θ = 
( take the square root of both sides )
tanΘ = ± 
Since 270 < Θ < 360 , that is the fourth quadrant where tan Θ < 0, thus
tanΘ = -
