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3 years ago

Which expression correctly represents eight times the difference of 4 and a number

Mathematics

1 answer:

expeople1 [14]3 years ago

6 0

Answer:

The expression for two times the difference of 4 and a number is

$8(4-d)$

Step-by-step explanation:

To Find:

Write an expression for Eight times the difference of 4 and a number.

Solution:

Let the Unknown number be 'd'

Difference of 4 and d = ( 4 - d )

So One Time Difference of 4 and d = 1× ( 4 - d )

∴ Two Times Difference of 4 and d = 2× ( 4 - d )

∴ Eight Times Difference of 4 and d = 8× ( 4 - d )

The expression for Eight times the difference of 4 and d. will be

$8(4-d)$

The expression for Eight times the difference of 4 and a number is

$8(4-d)$

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We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

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We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

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Alternate Hypothesis, $H_A$ : $\mu$ < 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean duration of 15-sided union rugby games = 179 min

s = sample standard deviation = 12 minutes

n = sample of 15-sided rugby games = 36

So, the test statistics = $\frac{179-185}{\frac{12}{\sqrt{36} } }$ ~ $t_3_5$

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The value of t test statistics is -3.

Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

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