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Answer:
h(t) = -16t2 + 144
h(1) = -16(12) + 144 = 128 ft
h(2) = -16(22) + 144 = 80 ft
h(2) - h(1) = 80 - 128 = -48 ft
It fell 48 ft between t = 1 and t = 2 seconds.
It reaches the ground when h(t) = 0
0 = -16t2 + 144
t = √(144/16) s = 3s
It reaches the ground 3s after being dropped.
Step-by-step explanation:
Answer:
620
Step-by-step explanation:
55800/90
C is the solution to the problem
In similar figures, the angle measures are the same but the side lengths are different. So in #4, x = 42. Since all the angles of a quadrilateral added up equal 360, then y is 360-90-90-42=138. For number 5, make sure you match up the sides correctly in your ratio:

. You could cross multiply to get 4x=16, and x = 4, or you could just realize that reducing 4/8 will give you 2/4 and x = 4. Going back to the idea that in similar shapes corresponding angles are the same measure, x in #6 is 63