Triangle XYZ is translated 4 units up and 3 units left to yield ΔX′Y′Z′. What is the distance between any two corresponding poin
ts on ΔXYZ and ΔX′Y′Z′?
1 answer:
see attachment
if you move the whole triangle up 4 units and to the left 3 units without rotating or dialating it, then each point should move up 4 units and 3 units to the left
find the distance between the first point and the translated point
if we draw out the path, we can see that the path makes 2 legs of a right triangle. the distance between the start and end is the hypotonuse
the 2 legs are length 3 and 4
by the pythagorean theorem, d²=3²+4²
d²=9+16
d²=25
d=5
so the distance between any 2 points on the original triangle and the translated triangle is 5 units
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(-6,-4)
If you dilate a point, (c,d) about (a,b) by a scale factor by k. You'll going to subtract each coordinates where the point will be dilated about (a,b) from the point (c,d) and then multiply them by k. This would be the formula if you want: (k(c -a), k(b -d))
Let's say F is the dilation of D about the origin or (0,0) then the x coordinate of F would be
This would be the y coordinate of F:
Thus the coordinates of F is (-6,-4)
<span>A
student divided the given number by 100 that resulted to 28.003 in his chart.
So what we are looking for this situation is the value of the number before it
was divided by 100.
To get the value, simply multiply the result by 100
=> 28.003 x 100
=> 2800.3
by dividing 100 to the given number, we simply move the value to the right in a value of hundreds.
See attached Image.
</span>
To get the value, simply multiply the result by 100
=> 28.003 x 100
=> 2800.3
by dividing 100 to the given number, we simply move the value to the right in a value of hundreds.
See attached Image.
</span>