Triangle XYZ is translated 4 units up and 3 units left to yield ΔX′Y′Z′. What is the distance between any two corresponding poin
ts on ΔXYZ and ΔX′Y′Z′?
1 answer:
see attachment
if you move the whole triangle up 4 units and to the left 3 units without rotating or dialating it, then each point should move up 4 units and 3 units to the left
find the distance between the first point and the translated point
if we draw out the path, we can see that the path makes 2 legs of a right triangle. the distance between the start and end is the hypotonuse
the 2 legs are length 3 and 4
by the pythagorean theorem, d²=3²+4²
d²=9+16
d²=25
d=5
so the distance between any 2 points on the original triangle and the translated triangle is 5 units
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Answer:
Choice B and Choise C.
Step-by-step explanation:
Equivalent expressions are those expressions that have the same value but they look different.
Given the following expression provided in the exercise:
You need to remember the multiplication of signs in order to find the equivalent expressions:
Then:
- Eliminating the parentheses, you get this equivalent expression:
- Since the mulplication of two negative signs gives yous a positive sign, you can rewrite the original expression in this form:
This is an equivalent expression to