Well, we can see that 115x refers to something that increases by 115 per purchase, while the 100 refers to a one time cost. Out of the possible answers the only one time charge is the installation charge, which refers to the 100$, and the 115x refers to the computers. In 115x, the 115 refers to how much a computer costs, and the x refers to the number of computers.
3k + 30m (I think that’s what it’s asking for!)
Answer:
10,000
Step-by-step explanation:
"The number who have been vaccinated against both is twice the number who have been vaccinated only against mumps."
Let b = number of children vaccinated against both.
Let m = number of children vaccinated only against mumps.
b = 2m
"If 5,000 have been vaccinated against both"
5000 = 2m
m = 2500
5000 children are vaccinated against both.
2500 children are vaccinated only against mumps.
The total number vaccinated against mumps is the number vaccinated only against mumps plus the number vaccinated against both:
2500 + 5000 = 7500
"the number of children who have been vaccinated against rubella is twice the number who have been vaccinated against mumps."
total number of children vaccinated against rubella = 2 * 7500 = 15,000
5000 of those children are vaccinated against both.
15,000 - 5000 = 10,000
10,000 children are vaccinated only against rubella.
Answer: 10,000
Answer: minimum = 0.5
maximum = 9.0
first quartile = 3
median = 5.5
third quartile = 7.5
Step-by-step explanation:
The histogram is shown below and used to obtain the various information
Time (hour) (X) No of People (F) FX
0.5 19 9.5 -- minimum = 0.5
1 20 20
1.5 21 31.5
2 22 44
2.5 23 57.5
3 24 72 ----first quartile = 3
3.5 26 91
4 27 108
4.5 28 126
5 29 145
5.5 30 165 --median/ inter quartile =5.5
6 31 186
6.5 32 208
7 33 231
7.5 34 255-- third quartile = 7.5
8 35 280
8.5 36 306
9 37 333 --- maximum = 9
T=85.5 T = 507 T= 2666.82 T = TOTAL
mean = sumFX/sumF = 2666.82/507 = 5.26
Median = middle number = inter quartile =5.5 (507/2 = 253.5 = 254 and add the frequency from top = 19+20+21+ 22+ 23+ 24+26+ 27+ 28+ 29 =269
and 254 close to 269 that is the frequency is within the range and corresponds to 5.5
first quartile = 1/4 *507 = 126.75 = 127 ( add the frequency from top= 19+20+21+ 22+ 23+ 24= 129 and 127 is close to 129)
third quartile = 3/4 * 507 = 380.25 ( add the frequency from top = 19+20+21+ 22+ 23+ 24+26+ 27+ 28+ 29+ 30+ 31+32+ 33+ 34 = 399 and 380 is close to 399 so the third quartile is 7.5
minimum is the one with lowest frequency = 0.5 at 19
maximum or mode is the one with highest frequency = 9 at 37
So slope is rise/run so 5/1 would be your slope. Hope this helped.