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olga2289 [7]
2 years ago
13

A regular hexagon is a six sided figure with all sides equal and all six angles equal. Find the length of the sides if the perim

eter of the regular hexagon is 102 cm.
Mathematics
1 answer:
KiRa [710]2 years ago
3 0

Answer:

17cm per side

Step-by-step explanation:

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Nia answered 80% of the 40 questions on a test correctly. How many correct answers did she have?
Step2247 [10]

Nia answered correct answers = 80% of the 40 questions

When we remove % sign from a number, we divide that number by 100

= \frac{80}{100} of 40

=\frac{80}{100} \times 40

Cancelling the two zeroes from numerator and denominator,

= 8 \times 4

= 32.

Total correct answers answered by Nia = 32

3 0
3 years ago
Read 2 more answers
The graph shows a transformation of circle M to circle N. Which statement describes the transformation of circle M to circle N?
d1i1m1o1n [39]

Answer:

C

Step-by-step explanation:

Got it right on ed 2021

3 0
3 years ago
I want help ,i want an answer
Otrada [13]

Answer:

1,900,800

Step-by-step explanation:

5 0
3 years ago
Can you guy help for this questing <br> 1234
postnew [5]

Answer:

1. Median

2. Altitude

3.  Altitude

4. Neither

Step-by-step explanation:

Median- splits the side into two congruent parts

Altitude- Makes a right  angle

1. Splits the side. Median

2. Makes a right angle. Altitude

3.  Makes a right angle. Altitude

4. Doesn't make a right  angle or split the sides. Neither

4 0
3 years ago
According to Masterfoods, the company that manufactures M&amp;M’s, 12% of peanut M&amp;M’s are brown, 15% are yellow, 12% are re
Anna35 [415]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

P(brown) = 12% = 0.12

P(Yellow) = 15% = 0.15

P(Red) = 12% = 0.12

P(blue) = 23% = 0.23

P(orange) = 23% = 0.23

P(green) = 15% = 0.15

A.) Compute the probability that a randomly selected peanut M&M is not yellow.

P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85

B.) Compute the probability that a randomly selected peanut M&M is brown or red.

P(Brown) or P(Red) :

0.12 + 0.12 = 0.24

C.) Compute the probability that three randomly selected peanut M&M’s are all brown.

P(brown) * P(brown) * P(brown)

0.12 * 0.12 * 0.12 =0.001728

D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.

P(3 blue)' = 1 - P(3 blue)

P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167

1 - P(3 blue) = 1 - 0.012167 = 0.987833

If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.

P(1 blue) + p(2 blue) + p(3 blue)

(0.23) + (0.23*0.23) + (0.23*0.23*0.23)

0.23 + 0.0529 + 0.012167

= 0.295067

5 0
3 years ago
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