Answer:
Step-by-step explanation:
3000 600
5000 1000
6000 1200
7500 1500
No it doesn't form a proportional relationship because yes, the ratio is constant AFTER the 5,000, you do need to hit the 5,000 first, and then it changes. So no, it's not proportional because it isn't constant throughout the entirety of the relationship. If you're just going based on the table in question, then yes it will be proportional since it doesn't have the 5,000 in it but if you're looking at it in it's entirety, no it's not.
Answer:
Step-by-step explanation:
The mean SAT score is
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it
) is

Next they draw a random sample of n=70 students, and they got a mean score (denoted by
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
Answer:
i do not know srry
Step-by-step explanation:
i think u should try and solve it with a better teacher
Answer:
46 customers
Step-by-step explanation:
If the number of original customers is n, we can write the following equation:
98 = 2n + 6
92 = 2n
46 = n