A company is purchasing new computers for its new office. The expression below represents the total cost of the computers, inclu
2 answers:
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Answer:
- 103.7
Step-by-step explanation:
Given:
Focal length of the eyepiece, f = 2.0 cm
Focal length of the objective lens, f' = 0.50 cm
Separation for minimum eyestrain = 6,0 cm
Image distance, v = - 25 cm
Now, from the lens formula,
here, u is the object distance
on substituting the respective values, we get
or
u = 1.852 cm
also, the separation is adjusted for minimum eyestrain,
therefore, image distance for the objective lens, v' = 6 - 1.852 = 4.148 cm
Now, for the objective lens
using the lens formula, we get
Here, u' is the distance between the physical object and objective lens
or
u' = 0.568 cm
Thus,
Magnification, m =
or
m =
or
m = - 103.7
Answer:
The 90% confidence interval would be given by (60.09;69.91)
We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.
Step-by-step explanation:
1) Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean for the sample
population mean (variable of interest)
s=9 represent the sample standard deviation
n=11 represent the sample size
2) Confidence interval
The confidence interval for the mean is given by the following formula:
(1)
In order to calculate the critical value we need to find first the degrees of freedom, given by:
Since the Confidence is 0.90 or 90%, the value of and
, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,10)".And we see that
Now we have everything in order to replace into formula (1):
So on this case the 90% confidence interval would be given by (60.09;69.91)
We are 90% confident that the true mean for the speeds of vehicles traveling on a highway is between 60.09 and 69.91 miles per hour.