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Mashcka [7]
3 years ago
11

Joy went to the community swap meet, where the cost to get in is $2. She plans to buy some candles for $1.60 each. If Joy has $5

0, how many candles can she buy after she pays to get in? *​
Mathematics
1 answer:
vlada-n [284]3 years ago
5 0

The answer is 30

Step-by-step explanation:

50-2=48 then divide 48 by 1.60 and you get 30!

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If the digits of a three-digit number are reversed in order, then the sum of the new resulting number and the original number co
Makovka662 [10]
First we have to setup system of equations for the given case.
Let x is the original number and y is the reverse three digit number.
Then,
x+y=665  Equation 1
x-y=297 Equation 2
Add both equations to get.
2x=962
Divide both sides by 2.
x=481
This is the original number. And reverse number is : 481+y=962
y=184

Here Hundredth digit is 4, and tenth digit is 8 which is 2 times of the hundredth digit. 

Answer: Number is 481

6 0
3 years ago
The square root of a whole number is between 600 and 700. The whole number must be between:
lyudmila [28]

Answer:

24 and 27

Step-by-step explanation:

√600 = 24.4

√700 = 27.7

So, the numbers should be around 24 and 27

thus you have option 3

7 0
3 years ago
On Monday, Dalaya had $15. On Tuesday, she bought a t-shirt for $12. On Wednesday, she found $5.50 on the street. On Friday, she
charle [14.2K]

Answer:

15-12+5.5+3-8

 

Step-by-step explanation:

15-12=3

3+5.5=8.5

8.5+3=11.5

11.5-8=3..5

3 0
3 years ago
Read 2 more answers
Can you please help me with this?
vfiekz [6]
D = -1<x<5
R = -3<y<3
ps can I have a brainliest
3 0
3 years ago
Find the 7th term of the expansion of (3c + 2d)9.
SIZIF [17.4K]
\bf (3c+2d)^9\\\\&#10;-------------------------------\\\\&#10;&#10;\begin{array}{crcll}&#10;term&&value\\&#10;-----&&-----\\&#10;1&&(3c)^9(2d)^0\\&#10;2&+9&9(3c)^8(2d)^1\\&#10;3&+36&(3c)^7(2d)^2\\&#10;4&+84&(3c)^6(2d)^3\\&#10;5&+126&(3c)^5(2d)^4\\&#10;6&+126&(3c)^4(2d)^5\\&#10;7&+84&(3c)^3(2d)^6\\&#10;\end{array}

now.. if you notice, the exponent for the 1st term, is dropping on each term subsequently, start with highest, 9 in this case, and drops drops drops, till on the last term, will be 0

the exponent for the second term, starts off at 0, and goes up up and up on each term

that part is simple... now, the coefficient for them

the first one will have a coefficient of 1, so we can take a closer look at the 2nd instead

the coefficient for the second is 1* 9/ 1
(1) the coefficient of the current term, (9) the exponent of the 1st term, and (1) the exponent of the 2nd term on the next term

for example, how did we get 84 for the 4th term?   (36 * 7) / 3 = 84

and so on for all subsequent terms
8 0
3 years ago
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