Set up 2 different equations for each day and then solve using substitution or elimination
Equation of the line:
y = -1.5x – 9
or
y =
- 3 x
2
– -9
When x=0, y = -9
When y=0, x = -6
Mark brainliest please
Hope this helps you
Answer:
c is the answer
Step-by-step explanation:
Answer:
3 11/20 miles
Step-by-step explanation:
Monday = seven -quarters of a mile
= 7/4 miles
Tuesday = nine-fifths of a mile
= 9/5 miles
How many miles did she ride altogether?
Total miles she rode altogether = Monday + Tuesday
= 7/4 + 9/5
= (35+36)/20
= 71/20
= 3 11/20
Total miles she rode altogether = 3 11/20 miles
Answer:
4 days
Step-by-step explanation:
We need to use the probability functions of each of the intervals to know the Probability number and then use it in the expected value.
P(x>3 cargo ships) = 1-P(x<=3)
P(x>3) = 1-P(x<=3)
P(x>3) = 1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)]
![P(x>3) = 1 - [\frac{e^{-2}2^0}{01}+\frac{e^{-2}2^1}{11}+\frac{e^{-2}2^2}{21}+\frac{e^{-3}2^3}{31}]](https://tex.z-dn.net/?f=P%28x%3E3%29%20%3D%201%20-%20%5B%5Cfrac%7Be%5E%7B-2%7D2%5E0%7D%7B01%7D%2B%5Cfrac%7Be%5E%7B-2%7D2%5E1%7D%7B11%7D%2B%5Cfrac%7Be%5E%7B-2%7D2%5E2%7D%7B21%7D%2B%5Cfrac%7Be%5E%7B-3%7D2%5E3%7D%7B31%7D%5D)
P(x>3) = 1- [0.1353(1+2+2+1.33)]
P(x>3) = 1-0.856
P(x>3) = 0.1431
Als n=30, expected number is
E(x) =30*P(x>3)
E(x) = 30*0.1431
E(x) = 4.293
I expect 4.293 or 4 days per month the block being unable to hanlde all arriving ships