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mash [69]
2 years ago
15

I need help simple explanation if possible

Mathematics
1 answer:
Yuki888 [10]2 years ago
8 0
Answer: X=1

Step-by-step explanation:
The hypotenuse is √2 which means that x²+x²=(√2)² using Pythagoras
Simplify and solve
2x²=2
x²=1
X=√1
X=1
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A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).
maksim [4K]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}

\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}

3 0
2 years ago
PLEASE HELP 15 POINTS
mart [117]
Area Y Square + Area of triangle
= 10x10+1/2x18x5
=100+9x5
=100+45
=145.
8 0
3 years ago
What does the absolute value 15 - 0 equal?<br>​
Phoenix [80]

Answer:

25

Step-by-step explanation:

dababy go yeayea

7 0
3 years ago
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Verizon [17]
+ & -
X & divide
Hope this helps!
6 0
3 years ago
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Pierre has more money than alex.
Lelechka [254]

Answer:

p = 2a-22

a= p-20

these will help you find the actual value

Step-by-step explanation:

this is not for the actual value

pierre = p

alex = a

p = a+20

p-20 = a

p+22 = 2a

p = 2a-22

7 0
2 years ago
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