<span>=<span><span><span><span><span>(3)</span><span>(x)</span></span>+<span><span>(3)</span><span>(4)</span></span></span>+<span><span>(2)</span><span>(<span>5x</span>)</span></span></span>+<span><span>(2)</span><span>(2)
</span></span></span></span><span>=<span><span><span><span>3x</span>+12</span>+<span>10x</span></span>+<span>4
</span></span></span><span>=<span><span><span><span>3x</span>+12</span>+<span>10x</span></span>+4
</span></span><span>=<span><span>(<span><span>3x</span>+<span>10x</span></span>)</span>+<span>(<span>12+4</span>)
</span></span></span><span>=<span><span>13x</span>+<span>16
Answer = </span></span></span><span>13x</span>+<span>16
(hope this helps)</span>
Answer:
1 represents the number of years passed.
step -by-step explanation:
The amount of a radioactive isotope decays in half every year. The amount of the isotope can be modeled by f(x) = 346 (1/2)x and f(1) = 173
Here 1 represents the number of years that passed.
So 1 represents the number of years.
Hope this will helpful.
Thank you.
Answer:
Read step by step explanation
Step-by-step explanation:
The owner already knows that the limit for the average time delivered pizzas is 38 minutes. So we conclude
1.-The resulting mean from sample data ( x ) ( 27 customers) need to be smaller than 38 minutes, any value of sample above 38 minutes means more time for the delivery action and will indicate a failure for the future project
2.-As sample size is smaller than 30 the test has to be t-student one tail test to the left
Test hypothesis
Null hypothesis H₀ x = 38
Alternative hypothesis Hₐ x < 38
We should test at a significance level α = 0,05 (α = 5%)
If the result of the test is to accept H₀ delivery project won´t be implemented, if on the other hand, H₀ is rejected then in the condition of the alternative hypothesis we accept Hₐ the sample indicates that we have a smaller average time than 38 minutes.
Answer:
Step-by-step explanation:
If you are always included to lead, that leaves 10 students to choose from.
If all that is important is being selected, then there are 10C3 = 120 ways to choose them.
If each selection has a unique duty, then there are 10P3 = 720 ways to assign them their jobs.
